Question

我一直在一个项目中创建时间表遵守情况，我已经订购了实时时间和时间表时间以获取这两者之间的百分比。但是我实时发现了一个障碍。有些员工将午餐从电话中脱机，而不是设置辅助状态。这是一个示例：

CCMS ID | Exception | LoginTime | LogoutTime | LogoutDate
--------+-----------+-----------+------------+-----------
2747738 | Open      | 09:31:00  | 12:25:00   | 2018-06-19
2747738 | AUX 1     | 12:25:00  | 12:35:00   | 2018-06-19
2747738 | Open      | 12:35:00  | 14:00:00   | 2018-06-19
2747738 | Open      | 15:00:00  | 16:35:00   | 2018-06-19
2747738 | AUX 8     | 16:35:00  | 16:38:00   | 2018-06-19
2747738 | Open      | 16:38:00  | 17:30:00   | 2018-06-19
2747738 | AUX 1     | 17:30:00  | 17:40:00   | 2018-06-19
2747738 | Open      | 17:40:00  | 18:33:00   | 2018-06-19

从上面可以看到，时间是无法计算的。请注意，在14:00至15:00之间没有时间条目。我要完成的工作是考虑所有时间，如下所示。在这里，您可以看到在14:00至15:00之间有一个新的“打开”条目，因此可以考虑一天中的所有时间：

  CCMS ID | Exception | LoginTime | LogoutTime | LogoutDate
  --------+-----------+-----------+------------+-----------
  2747738 | Open      | 09:31:00  | 12:25:00   | 2018-06-19
  2747738 | AUX 1     | 12:25:00  | 12:35:00   | 2018-06-19
  2747738 | Open      | 12:35:00  | 14:00:00   | 2018-06-19
  vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
>>2747738 | Open      | 14:00:00  | 15:00:00   | 2018-06-19<< Created entry here
  ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
  2747738 | Open      | 15:00:00  | 16:35:00   | 2018-06-19
  2747738 | AUX 8     | 16:35:00  | 16:38:00   | 2018-06-19
  2747738 | Open      | 16:38:00  | 17:30:00   | 2018-06-19
  2747738 | AUX 1     | 17:30:00  | 17:40:00   | 2018-06-19
  2747738 | Open      | 17:40:00  | 18:33:00   | 2018-06-19

我希望以您的知识来实现这一目标。预先谢谢你。

Answer 1

如果您使用MSSQL，这是解决方案（我将表命名为 T4 ）

SELECT
    RES.[CCMS ID]
    , CASE WHEN U.[NR]=1 THEN '**hole**' ELSE RES.[Exception] END AS [Exception]
    , CASE WHEN U.[NR]=1 THEN  RES.[LogoutTime] ELSE RES.[LoginTime] END AS [LoginTime]
    , CASE WHEN U.[NR]=1 THEN  RES.[B LoginTime] ELSE RES.[LogoutTime] END AS [LogoutTime] 
    , RES.[LogoutDate] 
FROM
(
    SELECT 1
    UNION
    SELECT 2
) U(NR)
INNER JOIN 
    (
    SELECT
    A.[CCMS ID], A.[Exception], A.[LoginTime], A.[LogoutTime], A.[LogoutDate] 
    ,B.[CCMS ID] AS [B CCMS ID], B.[Exception] AS [B Exception], B.[LoginTime] AS [B LoginTime], B.[LogoutTime] AS [B LogoutTime], B.[LogoutDate] AS [B LogoutDate] 
    ,CASE WHEN A.[LogoutTime]<>B.[LoginTime] THEN 1 ELSE 2 END AS [hole]
    FROM
    T4 A
    LEFT JOIN T4 B ON 
        B.[CCMS ID]=A.[CCMS ID] 
        AND B.[LogoutDate]=A.[LogoutDate] 
        AND B.[LoginTime]>A.[LoginTime] 
        AND NOT EXISTS(
          SELECT * FROM T4 C WHERE 
            C.[CCMS ID]=B.[CCMS ID] 
            AND C.[LogoutDate]=B.[LogoutDate] 
            AND C.[LoginTime]<B.[LoginTime]
            AND C.[LoginTime]>A.[LoginTime]
          )
    ) RES ON 
            CASE WHEN RES.[hole]=1 THEN 1 ELSE 0 END=U.[NR]
            OR
            CASE WHEN RES.[hole] IN (1,2) THEN 2 ELSE 0 END=U.[NR]


CCMS ID Exception   LoginTime   LogoutTime  LogoutDate
2747738 Open    09:31:00.0000000    12:25:00.0000000    2018-06-19
2747738 AUX 1   12:25:00.0000000    12:35:00.0000000    2018-06-19
2747738 **hole**    14:00:00.0000000    15:00:00.0000000    2018-06-19
2747738 Open    12:35:00.0000000    14:00:00.0000000    2018-06-19
2747738 Open    15:00:00.0000000    16:35:00.0000000    2018-06-19
2747738 AUX 8   16:35:00.0000000    16:38:00.0000000    2018-06-19
2747738 Open    16:38:00.0000000    17:30:00.0000000    2018-06-19
2747738 AUX 1   17:30:00.0000000    17:40:00.0000000    2018-06-19
2747738 Open    17:40:00.0000000    18:33:00.0000000    2018-06-19

http://sqlfiddle.com/#!18/a0c23/24/0

在登录时间和注销时间之间指定离线时间

1 个答案: