Question

我已经在代码中声明了所有相关的字符串变量。我的问题是我的登录验证。单击按钮时，我试图验证文本文件中是否存在字符串。其布局为“用户名：john25，密码：john25”。谁能确切地告诉我我要去哪里

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    // TODO add your handling code here:]
    if(evt.getSource()==jButton1){
        boolean found = false;
        username = ("");
        password = ("");
        filepath =("doctorFiles.txt");

        username = jTextField1.getText();
        password = jPasswordField1.getText();

        try{
            x = new Scanner(new File(filepath));
            x.useDelimiter("[,\n]");

            while(x.hasNext() && !found ) {
                username = x.next();
                password = x.next();

                if(username.trim().equals(username.trim()) && password.trim().equals(password.trim()))
                {
                    found = true;
                   if(found==true){
                     welcomePage goback = new welcomePage();
                     goback.setVisible(true);
                     dispose(); 
                     }
                }
                x.close();
                System.out.println(found);

            }


        }

        catch(Exception e)
        {
            System.out.println("Error is "+ e);
        }
    }
}

Answer 1

为什么要在这里添加自己的变量：

username = jTextField1.getText();
password = jPasswordField1.getText();


username = x.next();
password = x.next();

这毫无意义，在您看来

 if(username.trim().equals(username.trim()) && password.trim().equals(password.trim()))

您正在比较同一个变量，它将始终为真。尝试创建新变量

String usernameFromTxt = x.next();
String passwordFromTxt = x.next();

if(usernameFromTxt .trim().equals(username.trim()) && usernameFromTxt .trim().equals(password.trim()))

Java登录验证不起作用？

1 个答案: