Question

我经常使用library（car）中的“ recode”功能来重新编码变量中的级别。直到今天，我的代码都可以正常工作，但是现在却使我出错。 df等没有任何变化，不确定发生了什么。
也许有人可以启发我！

我的数据框（示例）：

test<-structure(list(Avg.Salary = c("65000", "395", "82000", "128357", 
"95785", "95785"), Education = c("Doctorate", "Professional Degree", 
"Bachelor's", "Professional Degree", "Master's", "Master's"), 
Count = c("D", "D", "D", "D", "D", "364584"), Year = c(2017, 
2017, 2017, 2017, 2017, 2017)), row.names = c("540061", "540071", 
"540081", "540091", "540102", "540112"), class = "data.frame")

我的实际数据集中的水平：-

    Associate Degree           Associates           Bachelor's 
             205                   35                42446 
               D            Doctorate          High School 
           42902                 9846                  191 
        Master's    Missing Education           No Diploma 
           57644                  218                   79 
    Professional  Professional Degree         Some College 
             431                 6791                   60 
 Some College Credits 
             370

我的代码（到今天为止还正常！）：-

# Recode the education levels
test$Education<-recode(test$Education,
                 "c('Associate Degree','Associates','D','High School',
                    'No Diploma','Missing Education',
                    'Professional','Professional Degree','Some College',
                    'Some College Credits')='Others'")

错误：-Error: Argument 2 must be named, not unnamed

Answer 1

它对我来说是干净的会话。我猜测car::recode()与dplyr::recode()冲突。合格功能是否起作用？将recode替换为car::recode。

test$Education <- car::recode(test$Education,
                 "c('Associate Degree','Associates','D','High School',
                    'No Diploma','Missing Education',
                    'Professional','Professional Degree','Some College',
                    'Some College Credits')='Others'")

当我显式调用dplyr::recode()时，出现错误“错误：参数2必须命名，而不是未命名”。

test$Education <- dplyr::recode(...)

R：使用car :: recode函数

1 个答案: