Question

问题：

我有一些活动，在屏幕中间有共享按钮，共享标题，共享过程栏和容器，其中片段被替换了。

所以我有活动的viewmodel-ActivityViewModel 在它的内部有以下观测值：

val mNavigationToMainActivity = CompletableSubject.create()
val mNavigationToUsername = PublishSubject.create<Any>()
val mNavigationToPassword = PublishSubject.create<Any>()
val mNavigationToChangePassword = PublishSubject.create<LoginItem>()


val mProcessBar = PublishSubject.create<Int>()
val mContinueButtonEnabled = BehaviorSubject.createDefault(false)
val mContinueClick = PublishSubject.create<Any>()
val mChangeTitleSubject = BehaviorSubject.createDefault(false)
val mLoadingIndicatorSubject = BehaviorSubject.createDefault(false)

，在片段之间有共享的viewmodel，它调用FragmentViewModel。所有片段都使用相同的视图模型

现在的问题是片段的视图模型如何访问活动的视图模型？例如，当用户单击“登录”按钮时，我希望fragmentviewmodel可以访问活动的加载程序，然后可以访问Navigationtonext屏幕。

或者例如在验证输入时启用按钮

这就是我在这些之间进行通信的目的：

fun <T> PublishSubject<T>.bind(subject: PublishSubject<T>): Disposable {
    return subscribe({ subject.onNext(it) }, { throwable -> subject.onError(throwable) })
}

fun <T> BehaviorSubject<T>.bind(subject: BehaviorSubject<T>): Disposable {
    return subscribe({ subject.onNext(it) }, { throwable -> subject.onError(throwable) })
}

fun CompletableSubject.bind(subject: CompletableSubject): Disposable {
    return subscribe({ subject.onComplete() }, { throwable -> subject.onError(throwable) })
}

我让片段的视图模型扩展基本视图模型的活动性视图模型

所以这是敏捷的视图模型

打开类IntroViewModel：BaseViewModel（）{

val mNavigationToMainActivity = CompletableSubject.create()
val mNavigationToUsername = PublishSubject.create<Any>()
val mNavigationToPassword = PublishSubject.create<Any>()
val mNavigationToChangePassword = PublishSubject.create<LoginItem>()


val mProcessBar = PublishSubject.create<Int>()
val mContinueButtonEnabled = BehaviorSubject.createDefault(false)
val mContinueClick = PublishSubject.create<Any>()
val mChangeTitleSubject = BehaviorSubject.createDefault(false)


fun bind(introViewModel: IntroViewModel){
    mNavigationToUsername.bind(introViewModel.mNavigationToUsername).addDisposable()
    mNavigationToPassword.bind(introViewModel.mNavigationToPassword).addDisposable()
    mNavigationToChangePassword.bind(introViewModel.mNavigationToChangePassword).addDisposable()
    mNavigationToMainActivity.bind(introViewModel.mNavigationToMainActivity).addDisposable()
    mProcessBar.bind(introViewModel.mProcessBar).addDisposable()
    mContinueButtonEnabled.bind(introViewModel.mContinueButtonEnabled).addDisposable()
}

fun continueClicked() {
    mContinueClick.onNext(Any())
}

} 这是片段

class ChangePasswordViewModel(private val userRepository: UserRepository)
    : IntroViewModel() {

在每个片段的内部，我将活动的视图模型绑定到该片段的视图模型

 viewModel = ViewModelProviders.of(activity!!, viewModelFactory).get(ChangePasswordViewModel::class.java)
        viewModel.start(2,arguments?.getParcelable(LoginItem::class.simpleName))
    ViewModelProviders.of(activity!!, viewModelFactory).get(IntroViewModel::class.java).apply {
        viewModel.bind(this)
    }

讨厌，我真的不喜欢。你能帮我吗？

todo-mvvm-xxx-视图模型之间的通信

0 个答案: