Question

我有一个像这样的数据集：

category                 UK             US           Germany  
sales                    100000        48000        36000 
budget                   50000         20000        14000
n_employees              300           123          134  
diversified              1             0            1   
sustainability_score     22.8          38.9         34.5
e_commerce               37000         7000         11000   
budget                   25000         10000        10000
n_employees              18            22           7  
traffic                  150 mil       38 mil       12500 
subsidy                  33000         26000        23000  
budget                   14000         6000         6000
own_marketing            0             0            1

在数据集中，销售变量对应于总部的销售额。
e_commerce是e-commerce的销售，而budget之后的e_commerce实际上是公司e_commerce部分的预算。 subsisdy同样适用，subsidy变量对应于subsidy的销售额，而budget是subsidy的预算后的subsidy变量。我想将数据集转换为这样的内容（如果以英国为例）：

UK_main_sales UK_main_budget ... UK_e_commerce_sales UK_e_commerce_budget ...
100000        500000             37000               250000

，依此类推。我试图通过跟踪budget变量来对来自不同部门的变量进行分类，因为变量总是在出发后立即出现，但我没有成功。英国变量的完整列表应如下所示：

UK_main_sales
UK_main_budget
UK_main_n_employees
UK_main_diversified
UK_main_sustainability_score 
UK_e_commerce (we could also add sales but I think it is simpler without sales)
UK_e_commerce_budget
UK_e_commerce_n_employees
UK_e_commerce_traffic
UK_subsidy
UK_subsidy_budget
UK_subsidy_own_marketing

有什么想法吗？

Answer 1

我认为需要：

#get boolean mask for rows for split
mask = df['category'].isin(['subsidy', 'e_commerce'])

#create NaNs for non match values by where
#replace NaNs by forward fill, first NaNs replace by fillna
#create mask for match values by mask and replace by empty string
#join together 
df['category'] = (df['category'].where(mask).ffill().fillna('main').mask(mask).fillna('') 
                   + '_' + df['category']).str.strip('_')

#reshape by unstack 
df = df.set_index('category').unstack().to_frame().T
#flatten MultiIndex
df.columns = df.columns.map('_'.join)

print (df)
  UK_main_sales UK_main_budget UK_main_n_employees UK_main_diversified  \
0        100000          50000                 300                   1   

  UK_main_sustainability_score UK_e_commerce UK_e_commerce_budget  \
0                         22.8         37000                25000   

  UK_e_commerce_n_employees UK_e_commerce_traffic UK_subsidy  \
0                        18               150 mil      33000   

             Germany_main_n_employees  \
0              ...                                   134   

  Germany_main_diversified Germany_main_sustainability_score  \
0                        1                              34.5   

  Germany_e_commerce Germany_e_commerce_budget Germany_e_commerce_n_employees  \
0              11000                     10000                              7   

  Germany_e_commerce_traffic Germany_subsidy Germany_subsidy_budget  \
0                      12500           23000                   6000   

  Germany_subsidy_own_marketing  
0                             1  

[1 rows x 36 columns]

在熊猫中转置非结构化行

1 个答案: