Question

我是编程新手，现在已经努力解决问题3天了。帮助将不胜感激！我建立了一个石头/纸/剪刀游戏，但除了1件事外，它都可以正常工作：当P2（玩家2）输入r / p / s之外的其他内容时，程序会告诉它输入无效，然后跳回P1 （播放器1）输入-我希望它在P2继续进行，而不是再次从P1开始。现在我知道有大约100种方法可以更好地编写程序，但是我想使用当前代码对其进行修复-我猜是在另一个while循环之类的东西，但是尝试了无数的选项和组合却没有成功。有人帮忙吗？

def rps():
    if p1 == 'r' and p2 == 's':
        print('Congrats P1! ')
    elif p1 == 'r' and p2 == 'p':
        print('Congrats P2! ')
    elif p1 == 'p' and p2 == 's':
        print('Congrats P2! ')
    elif p1 == 'p' and p2 == 'r':
        print('Congrats P1! ')
    elif p1 == 's' and p2 == 'r':
        print('Congrats P2! ')
    elif p1 == 's' and p2 == 'p':
        print('Congrats P1! ')
    elif p1 == 'r' and p2 == 'r':
        print('Draw! ')
    elif p1 == 's' and p2 == 's':
        print('Draw! ')
    elif p1 == 'p' and p2 == 'p':
        print('Draw! ')

while True:
    p1 = input('Choice P1? r/p/s (Type "quit" to exit)')
    p1check = p1 == 'r' or p1 == 'p' or p1 == 's'
    if p1 == 'quit':
        print('Bye!')
        break
    elif p1check is False:
        print('Invalid choice P1! ')
        continue

    p2 = input('Choice P2? r/p/s (type "quit" to exit)')
    p2check = p2 == 'r' or p2 == 'p' or p2 == 's'
    if p2 == 'quit':
        print('Chow!!')
        break
    elif p2check is False:
        print('Invalid choice P2! ')
        continue

    rps()

Answer 1

您好，欢迎来到编程的美好世界：）

您离预期的结果不远，建议您添加一个循环，直到P2输入有效为止。

#this is to avoid a while true and a break instruction
play_the_game = true

while play_the_game:
    #I skip the P1 managing part for more readability

    p2check = false
    #Loop until the player 2 entries match the expected inputs
    while p2check == false:
        p2 = input('Choice P2? r/p/s (type "quit" to exit)')
        p2check = p2 == 'r' or p2 == 'p' or p2 == 's'
        if p2 == 'quit':
            print('Chow!!')
            #play_the_game is now false, the main loop will exit.
            play_the_game = false
            #I added 'p2check = true' to make sure the loop 'while p2check == false:' will exit.
            #You can use a break instruction instead of 'p2check = true' if you prefer
            p2check = true
        elif p2check is False:
            print('Invalid choice P2! ')

Answer 2

我建议将输入置于循环中。

ByteArrayResource resource = new ByteArrayResource(multipartFile.getBytes()){
    @Override
    public String getFilename() {
        return systemFile.getFilenameWithExtension();
    }
};

在其他语言中，这被认为是import sys p2 = "" while p2 != 'r' or p2 != 'p' or p2 != 's' or p2 != 'quit' p2 = input('Choice P2? r/p/s (type "quit" to exit)') if p2 == 'quit': #Handle quite logic sys.exit(0)循环。由于Do While是p2，因此在第一次执行时就进入了循环。然后，如果用户输入正确的输入，则循环将中断，否则将继续询问输入。

您现在拥有的只是继续循环而无需第二次输入。

构造一个python循环语句

2 个答案: