Question

回溯（最近通话最近）：在第21行的文件“ final.py”中 lpd = LicensePlateDetector（图片） TypeError：“模块”对象不可调用

我实际上是在两个文件中运行该程序，第一个是由此类函数组成的

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我在其中使用argparse的第二个文件

from collections import namedtuple
from skimage.filters import threshold_local
from skimage import segmentation
from skimage import measure
from imutils import perspective
import numpy as np
import imutils
import cv2
LicensePlate = namedtuple("LicensePlateRegion", ["success", "plate", "thresh", "candidates"])
class LicensePlateDetector:
    print("entered class")
    def __init__(self, image, minPlateW=60, minPlateH=20, numChars=7, minCharW=40):
        self.image = image
        self.minPlateW = minPlateW
        self.minPlateH = minPlateH
        self.numChars = numChars
        self.minCharW = minCharW
    def detect(self):
        lpRegions = self.detectPlates()
        for lpRegion in lpRegions:
            lp = self.detectCharacterCandidates(lpRegion)
            if lp.success:
                yield (lp, lpRegion)
    def detectCharacterCandidates(self, region):
        plate = perspective.four_point_transform(self.image, region)
        cv2.imshow("Perspective Transform", imutils.resize(plate, width=400))
        V = cv2.split(cv2.cvtColor(plate, cv2.COLOR_BGR2HSV))[2]
        T = threshold_local(V, 29, offset=15, method="gaussian")
        thresh = (V > T).astype("uint8") * 255
        thresh = cv2.bitwise_not(thresh)
        plate = imutils.resize(plate, width=400)
        thresh = imutils.resize(thresh, width=400)
        cv2.imshow("Thresh", thresh)
        labels = measure.label(thresh, neighbors=8, background=0)
        charCandidates = np.zeros(thresh.shape, dtype="uint8")
        for label in np.unique(labels):
            if label == 0:
                continue
            labelMask = np.zeros(thresh.shape, dtype="uint8")
            labelMask[labels == label] = 255
            cnts = cv2.findContours(labelMask, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
            cnts = cnts[0] if imutils.is_cv2() else cnts[1]
            if len(cnts) > 0:
                c = max(cnts, key=cv2.contourArea)
                (boxX, boxY, boxW, boxH) = cv2.boundingRect(c)
                aspectRatio = boxW / float(boxH)
                solidity = cv2.contourArea(c) / float(boxW * boxH)
                heightRatio = boxH / float(plate.shape[0])
                keepAspectRatio = aspectRatio < 1.0
                keepSolidity = solidity > 0.15
                keepHeight = heightRatio > 0.4 and heightRatio < 0.95
                if keepAspectRatio and keepSolidity and keepHeight:
                    hull = cv2.convexHull(c)
                    cv2.drawContours(charCandidates, [hull], -1, 255, -1)
        charCandidates = segmentation.clear_border(charCandidates)
        return LicensePlate(success=True, plate=plate, thresh=thresh,candidates=charCandidates)

我写了这些，然后使用cmd运行了名为python final.py -i California1.jpg的命令。其中final.py是由代码第二部分组成的文件名，即argparse一个，而加利福尼亚一个则是由车号牌组成的图像

Answer 1

Python不是Java。如果要访问一个类，则需要直接将其导入，或通过已导入的模块对其进行引用。所以：

import LicensePlateDetector
...
lpd = LicensePlateDetector.LicensePlateDetector(image)

或

from LicensePlateDetector import LicensePlateDetector
...
lpd = LicensePlateDetector(image)

这是PEP8建议将文件命名为lower_case_with_underscore.py的原因之一。

如何解决这个Python错误？

1 个答案: