如何编写AND组合的SQL？

Question

请检查所附表格。

我需要编写查询以获取同时具有tage_id和32的文档。

像select * from doc_tags where tag_id = 32 or tag_id = 26之类的东西将无法正常工作，因为我将获得两个文档都包含32、26和（32，26）。

我需要的文档的标签ID只有32 **，标签不是26。**

注意 我不能使用document_id作为参考。

Answer 1

select * from doc_tags dt1
where (
    select count(distinct tag_id) from doc_tags dt2
    where dt2.document_id = dt1.document_id and tag_id in (26, 32)
) = 2 and dt1.tag_id in (26, 32)

或

with data as (
    select *,
        count(distinct tag_id) over (partition by document_id) as matches
    from doc_tags where tag_id in (26, 32)
)
select * from data where matches = 2

Answer 2

我会计算文档在这两个标签之间具有的不同标签的数量：

SELECT   document_id
FROM     doc_tags
WHERE    tag_id IN (26, 32)
GROUP BY document_id
HAVING   COUNT(DISTINCT tag_id) = 2

Answer 3

如果仅在两个文档之间，则可以执行此操作

Select * 
from doc_tags a
join doc_tags b on a.document_id = b.document_id
where a.tag_id = 26 and b.tag_id = 32

Answer 4

尝试这种类型的SQL QUUERY

select * from doc_tags where tag_id IN (32,26)

Answer 5

DECLARE @RESULT TABLE(doc_name VARCHAR(255))

INSERT INTO @RESULT 
       SELECT document_id 
       from doc_tags 
       WHERE tag_id =26 AND document_id IN 
            (SELECT document_id 
             from #tmp 
             WHERE tag_id =32)

SELECT * 
FROM doc_tags 
WHERE document_id in (SELECT doc_name 
                      FROM @RESULT)

Answer 6

SELECT * FROM doc_tags WHERE tag_id = 32 and tag_id = 26 

上面只会返回tag_id的32和26

Answer 7

SELECT
  d1.*
FROM
  doc_tags AS d1
INNER JOIN
  doc_tags AS d2
ON
  d1.documentid = d2.documentid AND
  (
    d1.documentid = 26 AND d2.documentid = 32 OR
    d1.documentid = 32 AND d2.documentid = 26
  )
WHERE
  d1.id <> d2.id

Answer 8

您还可以使用min()/max()函数：

SELECT document_id
FROM doc_tags dt
WHERE tag_id IN (26, 32)
GROUP BY document_id
HAVING MIN(tag_id) <> MAX(tag_id);

Answer 9

<?php

Route::get('your-uri', function () {
    $user = \Auth::user();
    dd($user);
})->middleware('auth');