Question

在为字符串定义拆分条件时，我似乎遇到一些问题。该条件必须用于将字符串映射到字典。

中

我有一个类似的问题，但是那里给出的解决方案可能适用于该特定情况，但不是一个可靠的解决方案。

不适用于这样的文本：

da:,en:H a full-bodied, vinous  wine, which attracts wine connoisseurs with its well-balanced and lively bouquet. It combines crisp  with a rich taste and long-lasting finish. Wines from one single vintage form the basis of this exceptional  wine. som – sparkling since 1856,fr:,nl:,ru:

语言标签中的文本带有逗号，因此以后不能选择:。

任何有关更可靠解决方案的建议。我的意图是映射字符串，以便我可以获取信息，我正在寻找给定的语言标签。

Answer 1

我建议使用正则表达式；提供

语言是两个（小）字母词，后跟一列：ru:，en:
逗号,是分隔符：en: bla-bla-bla,ru: bla-bla-bla

你可以放

using System.Text.RegularExpressions;

...

string source = @"da:,en: H a full - bodied, vinous wine, which attracts wine connoisseurs with its well-balanced and lively bouquet.It combines crisp with a rich taste and long-lasting finish.Wines from one single vintage form the basis of this exceptional wine. som – sparkling since 1856,fr:,nl:,ru:";

Dictionary<string, string> result = Regex
  .Matches(source, @"(?<lang>[a-z]{2}:)(?<value>.*?)(?=\,[a-z]{2}:|$)")
  .OfType<Match>()
  .ToDictionary(match => match.Groups["lang"].Value.TrimEnd(':'),
                match => match.Groups["value"].Value);

Console.WriteLine(string.Join(Environment.NewLine, result
  .Select(pair => $"language: {pair.Key}; text: {pair.Value}")));

结果：

language: da; text: 
language: en; text:  H a full - bodied, vinous wine, which attracts wine connoisseurs with its well-balanced and lively bouquet.It combines crisp with a rich taste and long-lasting finish.Wines from one single vintage form the basis of this exceptional wine. som – sparkling since 1856
language: fr; text: 
language: nl; text: 
language: ru; text:

定义将字符串解析为字典的拆分条件

1 个答案: