Question

我对JavaScript和Mysql很陌生。 MySQL查询（我已经在JS的服务器端代码中运行过）以这种形式返回行

即console.log（rows）给出：-

[ RowDataPacket {
    id: 7080,
    post_author: 134,
    post_title: '99 Varieties Dosa, Indira Nagar',
    post_content: 'There',
    link: '99-varieties-dosa-indira-nagar',
    seo_keywords: null,
    seo_desc: null,
    seo_title: null,
    best_for: 'Dosas',
    special_info: '',
    also_serves: 'Dosas',
    'close-timing': '',
    address: '56, 9th A Main Road',
    direction_landmarks: 'Located in Indira Nagar',
    seating: 'Unavailable',
    longitude: '77.64097630979995',
    latitude: '12.9777060556',
    phone_no: '   ',
    image_url: null,
    location: 'Indira Nagar',
    cuisine: 'South Indian Tiffin',
    categories: 'Local Food',
    Tags: 'Mysore Masala Dosa' }]
[ RowDataPacket {...}]
[ RowDataPacket {...}]
[ RowDataPacket {...}]
[ RowDataPacket {...}]

如何访问RowDataPacket对象的位置键？

我尝试了rows[i].location，rows[i]["location"]，rows.location，rows[i].RowDataPacket.location等。

Answer 1

在执行console.log（rows）;时您将以JSON数组的形式获取数据，可以使用以下代码段进行访问：

$.each(rows, function(index, data){
// check your index & data details like below & perform other tasks
console.log('INDEX=', index);
consoel.log('DATA=', data);  // Here data will be an object
// to access individual key data like location, you can try below code
console.log('LOCATION=', data.location);
});

有关更多参考，您可以通过链接：https://api.jquery.com/each/

从SQL行访问键

1 个答案: