Question

这是我的代码，但不显示我的sql输出，而是显示0

<html>
<head>
</head>
<body>

<?php
$sql1 = "SELECT COUNT(c.enno) AS 'noreg' FROM dtr_empinfo c WHERE c.`stats` = 
'Regular'";
$query1 = $dbh -> prepare($sql);
$query1->execute();
$results=$query1->fetchAll(PDO::FETCH_OBJ);
$empcount=$query1->rowCount();
?>
<?php echo htmlentities($empcount);?>

</body>
</html>

Answer 1

您在此处使用“ $ sql 1 ”：

$sql1 = "SELECT COUNT(c.enno) AS 'noreg' FROM dtr_empinfo c WHERE c.`stats` = 
'Regular'";

，但是您在此处使用“ $ sql”：

$query1 = $dbh -> prepare($sql);

因此，您正在运行一个空的sql命令，因此返回0行。

此外，您的echo语句仅返回行数。有关回显实际结果的说明，请参见下面的代码。

我曾经测试过的完整代码：

<html>
    <head>
    </head>
    <body>

    <?php

        // Create PDO
        $dbh = new PDO("mysql:host=localhost;dbname=your_database_name", 'your_database_username', 'your_database_user_password');
        $dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, true);
        $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $sql = "SELECT COUNT(c.enno) AS 'noreg' FROM dtr_empinfo c WHERE c.`stats` = 'Regular'";
        $query1 = $dbh -> prepare($sql);
        $query1->execute();
        $results=$query1->fetchAll(PDO::FETCH_OBJ);
        $empcount=$query1->rowCount();



        // You're only requesting the row count with this statement:
        $empcount=$query1->rowCount();
        echo htmlentities($empcount);

        // If you want the actual SQL results, do this:
        echo $results[0]->noreg;

        ?>

        <!-- Or, you can echo it within the html, like this: -->
        <?php echo $results[0]->noreg; ?>
        <!-- No htmlentities needed, since it's just a number -->

    </body>
</html>

如何显示我的SQL输出到PHP？

1 个答案: