Question

正在处理具有以下对象的项目：

人
- id
车辆
- id
- 类型：文本

和用于所有者更改的所有者链接表

所有者更改
- old_person_id
- new_person_id
- vehicle_id
- 日期

我正尝试在人员的视图上添加一个自定义查询，该查询仅选择具有某种车辆类型的人（用于发送新闻通讯）。为此，我提供有关此人的车辆的一些有价值信息的唯一途径是通过

453                 //Conditions
454                 $conditions['receives_news'] = 1;
455                 $conditions['and'] = array("not" => array("email" => null), "not" => array("email" => ''));                        
456                 $conditions['Person.receives_news'] = '1'; 
457                 $conditions['LOWER(Vehicle.model) LIKE'] = strtolower("%$vehicleModel%");                                          
458                 //$conditions['Person.id'] = '1';//hitme                                                                           
459                 
460                 $this->Person->recursive = 2;//Limit to 1 if too slow and remove from view the Provider Name                       
461                 $joins = array();                                                                                                  
462                 $joins[] = array(
463                         'table' => 'owner_changes',
464                         'conditions' => 'Person.id = OwnerChange.new_person_id',                                                   
465                         'type' => 'INNER',
466                         'alias' => 'OwnerChange',                                                                                  
467                 );
468                 $joins[] = array(
469                         'table' => 'vehicles',
470                         'conditions' => 'OwnerChange.vehicle_id = Vehicle.id',                                                     
471                         'type' => 'INNER',
472                         'alias' => 'Vehicle',                                                                                      
473                 );
474                 $this->paginate = array('conditions' => $conditions,                                                               
475                         'group' => 'Person.id',                                                                                    
476                         'joins' => $joins,                                                                                         
477                         'maxLimit' => 250, 
478                         'limit' => 20);//Optional                                                                                  
479                 $data = $this->paginate();                                                                                         
480                 
481                 //debug($data, 4);
482                 $this->set(strtolower($this->name), $data);

我的问题是我在人和车辆之间拥有所有关联，我只想将它们限制为最新的关联（by date DESC LIMIT 1），并且联接的结构未考虑我输入的订购或限制条款。所以我有属于其他人的车辆！！！

我尝试了类似this post之类的尝试，但没有成功似乎通常是“ 每组最大的麻烦”（this question），即使在SQL级别上，我仍然没有答案

更新

我现在找到了足够的查询来获取我的结果，但是无法将其集成到cakephp中。查询为：

SELECT p.`id` AS person_id, p.`name`, p.`surname`, p.`email`, p.`city`, p.`receives_news` , v.`model`, v.`id` AS vehicle_id, o.date AS owner_change_date
FROM owner_changes o
JOIN people p on o.new_person_id = p.id
JOIN vehicles v on o.vehicle_id = v.id
JOIN (select oc.vehicle_id, max(oc.date) maxdate
      FROM owner_changes oc                       
      GROUP by oc.vehicle_id) last1  ON o.vehicle_id = last1.vehicle_id 
                                   and o.date = last1.maxdate
WHERE p.`receives_news` = '1' AND NOT (p.`email` = '') AND LOWER(v.`model`) LIKE '%mts%' 
ORDER BY v.`id` ASC, o.`date` DESC
LIMIT 200

Cakephp 2.1.3查询Habtm表字段以及限制和顺序

更新

0 个答案: