php SESSION帮助

Question

我需要显示登录用户的名字。但是我做了一个问题

如此。

"You have been successfully logged in as <?php echo $_SESSION['username']; ?>.&nbsp"

但用户名似乎显得空白..我只是以。登录。

Answer 1

你有没有......

• 将用户名写入此实际变量？
• 调用此页面时调用session_start()？

如果是，您可能需要向我们提供更多代码。

Answer 2

"You have been successfully logged in as <?php echo $_SESSION['username']; ?>.&nbsp"

更改为（试一试）

echo "You have been successfully logged in as
$_SESSION['username'] &nbsp"

+++更多

首先，您需要使用session_start()函数启动会话。请注意，此函数should be called before any output is generated!此函数初始化$ _SESSION超全局数组，您可以在其中存储数据。例如，让我们在会话中存储用户名。你可以这样做：

session_start();
$_SESSION['username'] = 'ineedhelp';

"You have been successfully logged in as <?php echo $_SESSION['username']; ?>.&nbsp"

您必须确保您的会话不是clean or destroy，而是阻止您的代码 您是否已使用此行销毁

//...more your code
unset($_SESSION['username']);//Check if you clean before output
"You have been successfully logged in as <?php echo $_SESSION['username']; ?>.&nbsp"
//...more your code

Chekc your phpinfo()

如果您在输出中向下滚动，您会找到一个包含会话设置的完整部分：

session
Session Support     enabled
Registered save handlers    files user
Registered serializer handlers  php php_binary wddx

Directive   Local Value     Master Value
session.auto_start  Off     Off
session.bug_compat_42   Off     Off

Answer 3

您是否试图查看HTML页面源代码？ ; - ）

你试图把PHP代码放在字符串内容中 显然它不起作用。

echo "You have been successfully logged in as ".htmlspecialchars($_SESSION['username']).".&nbsp"

会起作用。

或者你可以这样做

?>
You have been successfully logged in as 
<?php echo htmlspecialchars($_SESSION['username']); ?>.&nbsp
<?

Answer 4

嗯，您必须在这两个页面上都有session_start()，即您设置或获取$_SESSION['username'] 之前设置或获取它们。

并尝试print_r($_SESSION)（它将有助于调试）检查username是否设置session_start如果有警告消息也检查日志。