我正在尝试清空,然后使用从promise返回的值重新填充数组。但是,当我这样做时,并不总是将它们以相同的顺序添加回去。
$scope.$watch ('timeRange', function (newValue, oldValue, scope){
$scope.chartdata = []
//If a filter has changed, redraw all charts
if (newValue !== oldValue)
{
for(var i = 0; i< $scope.charts.length; i++){
$scope.draw($scope.charts[i]).then(function(value){
$scope.chartdata.push(value);
});
}
}
}, true);
正在与ng-repeat一起显示。
答案 0 :(得分:1)
由于您正在执行异步处理,因此可能无法保证解析的顺序。您可以使用索引i
代替push
$scope.$watch ('timeRange', function (newValue, oldValue, scope){
$scope.chartdata = []
//If a filter has changed, redraw all charts
if (newValue !== oldValue)
{
for(var i = 0; i< $scope.charts.length; i++){
$scope.draw($scope.charts[i]).then(function(i) { // create scope to capture i
return function(value) { $scope.chartdata[i] = value; };
}(i));
}
}
}, true);
UPD 示例仅用于演示@georgeawg范围的工作原理
var arr = [1, 2, 3];
for (var i = 0; i < arr.length; i++) {
setTimeout(function(i) {
return function() {
console.log(`Let's teach @georgeawg scopes ${i}`)
}
}(i), i * 1000)
}
或使用forEach
$scope.$watch ('timeRange', function (newValue, oldValue, scope){
$scope.chartdata = []
//If a filter has changed, redraw all charts
if (newValue !== oldValue)
{
$scope.charts.forEach(function(chart, i) {
$scope.draw(chart).then(function(value) {
$scope.chartdata[i] = value;
})
})
}
}, true);
或者使用Promise.all
或它的angularjs类似物$q.all
一次添加所有内容。
$scope.$watch ('timeRange', function (newValue, oldValue, scope){
$scope.chartdata = []
//If a filter has changed, redraw all charts
if (newValue !== oldValue)
{
$q.all($scope.charts.map(function(chart) {
return $scope.draw(chart)
}).then(function(chartdata) {
$scope.chartdata = chartdata;
})
}
}, true);
答案 1 :(得分:-1)
错误代码段
function randInt(min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
function asyncFunc(index) {
return new Promise((resolve) => {
setTimeout(() => resolve(index), randInt(0, 3000));
});
}
const results = [];
for (var i = 0; i < 5; i++) {
asyncFunc(i)
.then((ret) => {
results.push(ret);
});
}
setTimeout(() => {
console.log(results);
}, 4000);
带有片段的片段
我们可以在IEFF
函数内部传递数据的位置。
function randInt(min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
function asyncFunc(index) {
return new Promise((resolve) => {
setTimeout(() => resolve(index), randInt(0, 3000));
});
}
const results = [];
for (var i = 0; i < 5; i++) {
(function(j) {
asyncFunc(i)
.then((ret) => {
results[j] = ret;
});
})(i);
}
setTimeout(() => {
console.log(results);
}, 4000);
答案 2 :(得分:-1)
使用.map
和Promise.all
(或AngularJS中的$q.all()
)是实现此目的的一种干净方法。这样可以保持商品的顺序,并有一个额外的好处,即允许您检测何时已填充整个阵列。
从格雷戈里的答案中借用示例代码:
(注意::以下内容使用setTimeout
,new Promise
和Promise.all
来作为可运行的堆栈代码段提供简单的说明性演示在实际的AngularJS代码中,您不需要setTimeout
或new Promise
,而应使用$q.all
而不是Promise.all
,如最后的示例所示)< / p>
function randInt(min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
function delay(ms) {
return new Promise(function (resolve) { setTimeout(resolve, ms); });
}
function asyncFunc(value) {
return delay(randInt(0, 3000))
.then(function () {
console.log(value, 'finished');
return value * 2 + 1;
});
}
const origArray = [0, 1, 2, 3, 4];
Promise.all(origArray.map(asyncFunc))
.then(function (resultArray) {
console.log(resultArray);
});
将其应用于您的特定代码,我们将:
$scope.$watch ('timeRange', function (newValue, oldValue, scope){
$scope.chartdata = []
//If a filter has changed, redraw all charts
if (newValue !== oldValue)
{
$q.all($scope.charts.map($scope.draw))
.then(function (resultArray) {
$scope.charts = resultArray;
});
}
}, true);