Question

我有一个如下所示的JSON

{
    "packages": [
        {
            "screenings": [
                {
                    "data": {
                        "educationHistory": [
                            {
                                "school": "Test education 4"
                            },
                            {
                                "school": "Test education 4"
                            }
                        ]

                    }
                },
                {
                    "data": {
                        "educationHistory": [
                            {
                                "major": [
                                    "Business Admin."
                                ],
                                "school": "Test education 1"
                            },
                            {
                                "major": [
                                    "Business Admin."
                                ],
                                "school": "Test education 1"
                            }
                        ]

                    }
                }
            ]
        }
    ]
}

在dataweave中，我这样写

ns0#EmploymentHistory: {(
    payload.packages[0].screenings.data.educationHistory map {
        ns0#Employer: {
            ns0#EmployerName: $.school
        }
    }
)}

我正在得到这样的输出

<ns0:EmploymentHistory>
<ns0:Employer>
  <ns0:EmployerName>
    <school>Test education 4</school>
    <school>Test education 4</school>
  </ns0:EmployerName>
</ns0:Employer>
<ns0:Employer>
  <ns0:EmployerName>
    <school>Test education 1</school>
    <school>Test education 1</school>
  </ns0:EmployerName>
</ns0:Employer>
</ns0:EmploymentHistory>

我需要像下面的

<ns0:EmploymentHistory>
    <ns0:Employer>
      <ns0:EmployerName>
        <school>Test education 4</school>
      </ns0:EmployerName>
    </ns0:Employer>
    <ns0:Employer>
      <ns0:EmployerName>
        <school>Test education 4</school>
      </ns0:EmployerName>
    </ns0:Employer>
    <ns0:Employer>
      <ns0:EmployerName>
        <school>Test education 1</school>
      </ns0:EmployerName>
    </ns0:Employer>
    <ns0:Employer>
      <ns0:EmployerName>
        <school>Test education 1</school>
      </ns0:EmployerName>
    </ns0:Employer>
</ns0:EmploymentHistory>

此xpath payload.packages[0].screenings.data.educationHistory map {遍历screening而不是educationHistory

Answer 1

您需要使用后代选择器..来一次获取所有educationHistory的值。这将从父元素（在本例中为payload.packages[0]）中搜索整个树，并获取每个匹配的子元素（在本例中为educationHistory）。由于educationHistory在两个实例中都是一个数组，因此将返回一个数组数组，因此我们需要使用flatten来代替，而是使用对象数组：

%dw 1.0
%output application/xml

%var employers = flatten payload.packages[0]..educationHistory
---
{
  EmploymentHistory: {
    (employers map {
      Employer: {
        EmployerName: {
          School: $.school
        }
      }
    })
  }
}

您可以找到有关后代选择器here的信息。这是MuleSoft的官方说法：

[后代选择器]以..的形式应用于上下文，并在当前上下文下检索子树中所有匹配的key：value对的值。无论这些字段的组织层次结构如何，它们都将放置在输出中的同一级别。

在m子dataweave

1 个答案: