Question

我有一个多维数组，如下所示：

$arrayOne = array(
    0 => array(
        "no"=> "1",
        "value"=>100
    ), 
    1=> array(
        "no"=> "2",
        "value"=>"20"
    )
    2=> array(
        "no"=> "3",
        "value"=>"30"
    )
);

我想创建一个新的数组，其中：

1st new array value = 100+50 (equal to 150, where 50 is an amount that I want to add to the array).
2nd new array value = 20+150 (equal to 170, where 150 is the total of 1st new array)
3rd new array value = 30+170 (equal to 200, where 170 is the total of 2nd new array)

这可行吗？输出应为：

   $newArrayOne = array(
        0 => array(
            "no"=> "1",
            "value"=>150
        ), 
        1=> array(
            "no"=> "2",
            "value"=>"170"
        )
        2=> array(
            "no"=> "3",
            "value"=>"200"
        )
    );

这个要求对我来说有点太复杂了。谁能分享我这个概念，我会尽力弄清楚。

非常感谢。

Answer 1

类似的东西：

$arrayOne[0]['value'] += 50;
for($i=1; $i<count($arrayOne); $i++) {
    $arrayOne[$i]['value'] += $arrayOne[$i-1]['value'];
}

Answer 2

您可以使用经典 foreach循环

$arrayOne = //Your array here...

$newArrayOne  = array();
$toAdd = 50;

foreach( $arrayOne as $key => $val ) {
    $newArrayOne[$key] = $val;  //Assign the value to $newArrayOne

    if ( $key === 0 ) $newArrayOne[$key]['value'] += $toAdd;  //Modify the value: If $key is 0, add 50
    else $newArrayOne[$key]['value'] += $newArrayOne[ $key - 1 ]['value'];  //If $key is not 0, add the value of last entry of $newArrayOne
}

这将导致：

Array
(
    [0] => Array
        (
            [no] => 1
            [value] => 150
        )

    [1] => Array
        (
            [no] => 2
            [value] => 170
        )

    [2] => Array
        (
            [no] => 3
            [value] => 200
        )

)

Answer 3

$first_array = array(
0 => array(
    "no"=> "1",
    "value"=>100
), 
1=> array(
    "no"=> "2",
    "value"=>"20"
),
2=> array(
    "no"=> "3",
    "value"=>"30"
)
);

$to_be_added = 50; //this is what you want to add to your first value

foreach ($first_array as $key => $val){

  $to_be_added = (int)$val['value'] + $to_be_added ; //type casting
  $newArrayOne[$key]['no']= $val['no'];
  $newArrayOne[$key]['value']= $to_be_added; 


}

print_r($newArrayOne);

请注意im类型将您的值强制转换为整数，因为并非您的所有“值”都是整数。

您的输出

Array ( [0] => Array ( [no] => 1 [value] => 150 ) [1] => Array ( [no] => 2 [value] => 170 ) [2] => Array ( [no] => 3 [value] => 200 ) )

Answer 4

$ newArray = $ arrayOne;

foreach（$ arrayOne as $ k => $ v）{

$newArray[$k]['value'] = ($k == 0) ? array_sum(array_column($arrayOne, 'value')) : $newArray[$k-1]['value'] + $arrayOne[$k]['value'];

}

print_r（$ newArray）;

Answer 5

我为您付出了很多努力。我希望这对您有用。

<?php
echo "<pre>";
$arrayOne = array(
    0 => array(
        "no"=> "1",
        "value"=>100
    ), 
    1=> array(
        "no"=> "2",
        "value"=>"20"
    ),
    2=> array(
        "no"=> "3",
        "value"=>"30"
    )
);
$valnewarr = array();
$valdata = 50;
$i = 0;
foreach($arrayOne as $val){
$valdata = $val['value']+$valdata;
$valnewarr['no'] = ++$i;
$valnewarr['value']  = $valdata;
$newArrayOne[] = $valnewarr;
}
print_r($newArrayOne);
?>

PHP从现有数组创建新数组，并对新数组进行一些数学计算[多维]

5 个答案: