在https://hexdocs.pm/gen_stage/GenStage.html#module-init-and-subscribe_to,我用subscribe_to
选项定义了GenStage模块
defmodule A do
use GenStage
def start_link(number) do
GenStage.start_link(A, number)
end
def init(counter) do
{:producer, counter}
end
def handle_demand(demand, counter) when demand > 0 do
# If the counter is 3 and we ask for 2 items, we will
# emit the items 3 and 4, and set the state to 5.
events = Enum.to_list(counter..counter+demand-1)
{:noreply, events, counter + demand}
end
end
defmodule B do
use GenStage
def start_link(number) do
GenStage.start_link(B, number)
end
def init(number) do
{:producer_consumer, number, subscribe_to: [{A, max_demand: 10}]}
end
def handle_events(events, _from, number) do
events = Enum.map(events, & &1 * number)
{:noreply, events, number}
end
end
defmodule C do
use GenStage
def start_link() do
GenStage.start_link(C, :ok)
end
def init(:ok) do
{:consumer, :the_state_does_not_matter, subscribe_to: [B]}
end
def handle_events(events, _from, state) do
# Wait for a second.
Process.sleep(1000)
# Inspect the events.
IO.inspect(events)
# We are a consumer, so we would never emit items.
{:noreply, [], state}
end
end
如果我手动运行它们,它将起作用
iex(1)> GenStage.start_link(A, 0, name: A)
{:ok, #PID<0.195.0>}
iex(2)> GenStage.start_link(B, 2, name: B)
{:ok, #PID<0.197.0>}
iex(3)> GenStage.start_link(C, :ok)
{:ok, #PID<0.199.0>}
[0, 2, 4, 6, 8]
[10, 12, 14, 16, 18]
[20, 22, 24, 26, 28]
[30, 32, 34, 36, 38]
‘(*,.0’
然后建议将其添加到主管树中:
在监督树中,通常是通过启动多个 工人:
defmodule TestDep.Application do
@moduledoc false
use Application
def start(_type, _args) do
import Supervisor.Spec
children = [
worker(A, [0]),
worker(B, [2]),
worker(C, []),
]
opts = [strategy: :rest_for_one]
Supervisor.start_link(children, opts)
end
end
那是我的主管树,但是当使用iex -S mix
运行应用程序时,我收到:
**(混合)无法启动应用程序testdep:TestDep.Application.start(:normal,[])返回错误:关机: 无法启动孩子:B **(EXIT)无进程:该进程尚未运行或当前没有与该给定名称相关联的进程,可能是因为 应用程序未启动
我的应用在mix.ex
上的定义为
def application do
[
extra_applications: [:logger],
mod: {TestDep.Application, []}
]
end
有什么我想念的吗?
答案 0 :(得分:1)
如果我手动运行它们,它将起作用
它不是:( 有效的不是您要测试的东西,也不等同于您在监督树中开始的工作,这是:
A.start_link(0)
B.start_link(2)
C.start_link()
也就是说,您可能希望将名称传递给包装的GenStage.start_link
:
defmodule A do
use GenStage
def start_link(number) do
# ⇓⇓⇓⇓⇓⇓⇓⇓⇓ THIS
GenStage.start_link(A, number, name: A)
end
其余的都一样。