在传递给视图渲染（codeigniter）之前修改DB值？

Question

获取传递到$ data ['rowVideo']的数据库，但我想更改/修改数组中的值？这样做最好的方法是什么？

    $SQL = "SELECT * FROM video";
    $query = $this->db->query($SQL);
    $data['rowVideo'] = $query->fetchAll(PDO::FETCH_ASSOC);

    foreach ($data['rowVideo'] as $key => $value) {

     // do some  $data['rowVideo'] alteration
     // How would you do it?

    }



   $this->load->view('content', $data);

Answer 1

只是做：

$data['rowVideo'][$key] = $modifiedValueCreatedFromValue;