Java mergesort不起作用

时间:2018-06-26 07:55:52

标签: java algorithm recursion mergesort divide-and-conquer

我在Java中编写了mergesort(recursive)的代码。我尝试在IntelliJ中调试它,但是它什么也没做

public class Main {

    public static void main(String[] args) {
        int[] ar = {20, 35, -15, 7, 55, 1, -22};
        mergeSort(ar);
        System.out.println(Arrays.toString(ar));
    }

    private static void mergeSort(int[] arra) {
        int l=arra.length;
        int mid = l/2;
        int[] left= Arrays.copyOfRange(arra,0,mid);
        int[] right= Arrays.copyOfRange(arra,mid,l);
        mergeSort(left);
        mergeSort(right);
        merge(left,right,arra);

    }

    public static void merge(int[] ll,int[] rr,int[] array) {
        int nl = ll.length;
        int nr = rr.length;
        int l=0;int r=0;int a=0;
        while(l<=nl && r<= nr) {
            array[a++]=ll[l]<=rr[r] ? ll[l++] : rr[r++];
        }

        if (l<nl) {
            while (l <= nl)
                array[a++] = ll[l++];
        }

        if (r<nr) {
            while (r<=nr)
                array[a++] = rr[r++];
        }
    }

问题似乎在第21行,即“ mergesort(left);”

代码上也没有红色下划线,仍然没有,仍然没有结果。

1 个答案:

答案 0 :(得分:0)

mergeSort()中存在无限循环。在函数内部的代码周围放置一个if案例,如下所示:

private static void mergeSort(int[] arra) {
    if (arra.length > 1) {
        int l = arra.length;
        int mid = l / 2;
        int[] left = Arrays.copyOfRange(arra, 0, mid);
        int[] right = Arrays.copyOfRange(arra, mid, l);
        mergeSort(left);
        mergeSort(right);
        merge(left, right, arra);
    }
}

还可以在功能merge()中将<=替换为<,并且在类似情况下使用<< / p>:

while (l < nl && r < nr) {
    array[a++] = ll[l] <= rr[r] ? ll[l++] : rr[r++];
}

if (l < nl) {
    while (l < nl)
        array[a++] = ll[l++];
}

if (r < nr) {
    while (r < nr)
        array[a++] = rr[r++];
}