Question

从API获取2d数组时，正在解析响应。但是我无法获得这些值。

这就是得到回复的方式，

DefaultHttpClient httpclient = new DefaultHttpClient(new BasicHttpParams());
String api_uri = "http://192.168.0.106/api/something/";
HttpGet httpget = new HttpGet(api_uri);

httpget.setHeader("Content-type", "application/json");

InputStream inputStream = null;
String result = null;

try {
 HttpResponse response = httpclient.execute(httpget);
 HttpEntity entity = response.getEntity();

 inputStream = entity.getContent();
 // json is UTF-8 by default
 BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"), 8);
 StringBuilder sb = new StringBuilder();

 String line = null;
 while ((line = reader.readLine()) != null) {
  sb.append(line + "\n");
 }
 result = sb.toString();
 Log.e("rAct", result);
} catch (Exception e) {
 // Oops
 Log.e("rActEr", e.toString());
} finally {
 try {
  if (inputStream != null) inputStream.close();
 } catch (Exception squish) {}
}

result字符串如下，

[
    [
        {
            "id": 138,
            "name": "asdasd",
            "person_image": "http://something.in:9090/photos/14/1575.jpg",
            "person_description": "bla bla blaa",
            "bla_id": 1,
            "blabal_id": 2,
            "other_id": 7,
            "category": "asd"
        }
    ],
    [
        {
            "id": 257,
            "name": "asdasd",
            "person_image": "http://something.in/asd.jpg",
            "person_description": "asasdsad",
            "bla_id": 1,
            "blabal_id": 2,
            "other_id": 7,
            "category": "ASSSD"
        }
    ]
]

所以现在我试图读取数据，

try {
    jsonarray = new JSONArray(result);
    for (int i = 0; i < jsonarray.length(); i++) {
        jsonobject = jsonarray.getJSONObject(i);
        Log.e("testt", jsonobject.toString());
        ...
        ...
    }
}catch....

无法从该jsonobject获取任何信息如何从结果中获取name，person_image，person_description数据。我试图让它们像jsonobject.optString("name")一样，但一无所获。

使用一维数组，我得到了响应，并且可以按照上面相同的方式读取数据。

我需要修改什么才能读取所需的数据？

Answer 1

当您拥有数组数组时，尝试读取外部数组内部的 json数组而不是 object ：

try {
jsonarray = new JSONArray(result);
for (int i = 0; i < jsonarray.length(); i++) {
    jsonarrayInner = jsonarray.getJSONArray(i);
    //you can do one more loop here
    for (int i = 0; i < jsonarrayInner.length(); i++) {
        jsonobject = jsonarrayInner.getJSONObject(i);
        Log.e("testt", jsonobject.toString());
    }
    ...
    ...
}
}catch....

Answer 2

在这种情况下，我更喜欢将Gson与 POJO 一起使用，它将json数组包装到java.util.List of <YourPojo>

中

List<MyPojo> myPojoList= new Gson().fromJson(jsonArray.toString(), new TypeToken<List<MyPojo>>() {
                }.getType());

您的pojo应该与您的json属性匹配

所以您的课程应该是这样的

class MyPojo{
    private id;
    private String name ;
    private String person_image;
    private String person_description;
    private int bla_id;
    private int blabal_id;
    private int other_id;
    private String category;
}

通过这种方式，您将直接将json数组绑定到java对象

无法解析2D json数组并显示其内容

2 个答案: