每个级别都有房间列表。
每个房间都有一个事件列表。
一个事件包含对房间中物品及其数量的引用。
一篇文章有代码和费用。
如何获取每个级别的文章列表（按代码分组以汇总数量/成本）？
XML：
<planning>
<articles>
<article id="1" code="C12" name="chair" cost="20"/>
<article id="2" code="T1" name="table" cost="31"/>
<article id="3" code="L10" name="lamp" cost="10"/>
<article id="4" code="TA2" name="tap" cost="5"/>
<article id="5" code="B20" name="bed" cost="12"/>
</articles>
<rooms>
<room id="1" name="A1">
<occurrence-list>
<occurrence id="1" article-ref="1" qty="3"/>
<occurrence id="2" article-ref="4" qty="2"/>
<occurrence id="3" article-ref="5" qty="4"/>
</occurrence-list>
</room>
<room id="2" name="A2">
<occurrence-list>
<occurrence id="4" article-ref="1" qty="2"/>
<occurrence id="5" article-ref="2" qty="3"/>
</occurrence-list>
</room>
<room id="3" name="B1">
<occurrence-list>
<occurrence id="6" article-ref="1" qty="1"/>
<occurrence id="7" article-ref="3" qty="2"/>
<occurrence id="8" article-ref="4" qty="4"/>
</occurrence-list>
</room>
<room id="4" name="B2">
<occurrence-list>
<occurrence id="9" article-ref="2" qty="2"/>
<occurrence id="10" article-ref="5" qty="5"/>
</occurrence-list>
</room>
<room id="5" name="C1">
<occurrence-list>
<occurrence id="10" article-ref="1" qty="2"/>
<occurrence id="11" article-ref="3" qty="2"/>
<occurrence id="12" article-ref="4" qty="1"/>
</occurrence-list>
</room>
</rooms>
<level id="1" name="Level 1">
<level-room room-ref="1"/>
<level-room room-ref="3"/>
<level-room room-ref="5"/>
</level>
<level id="2" name="Level 2">
<level-room room-ref="2"/>
<level-room room-ref="4"/>
</level>
到目前为止，这是我的XSL：
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" encoding="utf-8" indent="no"/>
<xsl:key name="articles" match="article" use="@id"/>
<xsl:key name="room" match="room" use="@id"/>
<xsl:key name="room-occurrences" match="occurrence" use="../../@id"/>
<xsl:key name="level-rooms" match="level-room" use="../@id"/>
<xsl:template match="/">
<html>
<body>
<h2>Items per level</h2>
<table border="1">
<tr>
<td>Level</td>
<td>Article</td>
<td>Cost</td>
<td>Qty</td>
<td>Total</td>
</tr>
<xsl:for-each select="/planning/level">
<tr>
<td><xsl:value-of select="@name"/></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<xsl:for-each select="key('room-occurrences', key('level-rooms', @id)/@room-ref)">
<xsl:sort select="key('articles', @article-ref)/@code" order="ascending"/>
<tr>
<td></td>
<td><xsl:value-of select="key('articles', @article-ref)/@code"/></td>
<td><xsl:value-of select="key('articles', @article-ref)/@cost"/></td>
<td><xsl:value-of select="@qty"/></td>
<td><xsl:value-of select="@qty * key('articles', @article-ref)/@cost"/></td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
这是我得到的结果HTML：
+---------+------+-----+-------+ | Article | Cost | Qty | Total | +---------+------+-----+-------+ | Level 1 | +------------------------------+ | B20 | 12 | 4 | 48 | +---------+------+-----+-------+ | C12 | 20 | 3 | 60 | +---------+------+-----+-------+ | C12 | 20 | 1 | 20 | +---------+------+-----+-------+ | C12 | 20 | 2 | 40 | +---------+------+-----+-------+ | L10 | 10 | 2 | 20 | +---------+------+-----+-------+ | L10 | 10 | 2 | 20 | +---------+------+-----+-------+ | TA2 | 5 | 2 | 10 | +---------+------+-----+-------+ | TA2 | 5 | 4 | 20 | +---------+------+-----+-------+ | TA2 | 5 | 1 | 5 | +---------+------+-----+-------+ | Level 2 | +------------------------------+ | B20 | 12 | 5 | 60 | +---------+------+-----+-------+ | C12 | 20 | 2 | 40 | +---------+------+-----+-------+ | T1 | 31 | 3 | 93 | +---------+------+-----+-------+ | T1 | 31 | 2 | 62 | +---------+------+-----+-------+
但是我想按代码对文章进行分组，如下所示：
+---------+------+-----+-------+ | Article | Cost | Qty | Total | +---------+------+-----+-------+ | Level 1 | +------------------------------+ | B20 | 12 | 4 | 48 | +---------+------+-----+-------+ | C12 | 20 | 6 | 120 | +---------+------+-----+-------+ | L10 | 10 | 4 | 40 | +---------+------+-----+-------+ | TA2 | 5 | 7 | 35 | +---------+------+-----+-------+ | Level 2 | +------------------------------+ | B20 | 12 | 5 | 60 | +---------+------+-----+-------+ | C12 | 20 | 2 | 40 | +---------+------+-----+-------+ | T1 | 31 | 5 | 155 | +---------+------+-----+-------+
答案 0 :(得分：1)
由于您拥有独特的article元素，我认为一种方法是简单地使用已设置的键来选择它们（尽管在可能的情况下，我仅通过简单地使用子元素就将其缩短了一点），然后进行处理引用的article，回顾数量之和：
<xsl:key name="articles" match="article" use="@id"/>
<xsl:key name="room" match="room" use="@id"/>
<xsl:template match="/">
<html>
<body>
<h2>Items per level</h2>
<table border="1">
<tr>
<td>Level</td>
<td>Article</td>
<td>Cost</td>
<td>Qty</td>
<td>Total</td>
</tr>
<xsl:for-each select="/planning/level">
<tr>
<td><xsl:value-of select="@name"/></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<xsl:variable name="level-occs" select="key('room', level-room/@room-ref)/occurrence-list/occurrence"/>
<xsl:for-each select="key('articles', $level-occs/@article-ref)">
<xsl:sort select="@code" order="ascending"/>
<xsl:variable name="qty" select="sum($level-occs[@article-ref = current()/@id]/@qty)"/>
<tr>
<td></td>
<td><xsl:value-of select="@code"/></td>
<td><xsl:value-of select="@cost"/></td>
<td><xsl:value-of select="$qty"/></td>
<td><xsl:value-of select="$qty * @cost"/></td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>