Question

我具有呈现应用程序路由的以下组件：https://jsbin.com/bahaxudijo/edit?js，我正在尝试模拟BrowserRouter和Route来进行测试，这是我的测试：

import React from 'react';
import renderer from 'react-test-renderer';

import Router from '../../../components/Router/Component';

jest.mock('react-router-dom', () => ({
  BrowserRouter: ({ children }) => <div>{children}</div>,
  Route: ({ children }) => <div>{children}</div>,
}));

jest.mock('../../../components/Nav/index', () => '<MockedNav />');
jest.mock('../../../components/ScheduleManager/index', () => '<MockedScheduleManager />');

const props = {
  token: '',
  loginStaff: jest.fn(),
};

describe('<Router />', () => {
  describe('When is passed a token', () => {
    it('renders the correct route', () => {
      const component = renderer.create(<Router {...props} />);
      expect(component).toMatchSnapshot();
    });
  });
});

但是我嘲笑错误的BrowserRouter和Route，所以测试通过了，但是快照只是空的div。如何正确模拟BrowserRouter和路由？

Answer 1

jest.mock('react-router-dom', () => {
  // Require the original module to not be mocked...
  const originalModule = jest.requireActual('react-router-dom');

  return {
    __esModule: true,
    ...originalModule,
    // add your noops here
    useParams: jest.fn(),
    useHistory: jest.fn(),
  };
});

Answer 2

另一种方式：

const rrd = require('react-router-dom');

jest.spyOn(rrd, 'BrowserRouter').mockImplementation(({children}) => children);

来源：

Answer 3

const reactRouter = require('react-router-dom');
const { MemoryRouter } = reactRouter;
const MockBrowserRouter = ({ children }) => (
  <MemoryRouter initialEntries={['/']}>
    { children }
  </MemoryRouter>
);
MockBrowserRouter.propTypes = { children: PropTypes.node.isRequired };
reactRouter.BrowserRouter = MockBrowserRouter;

如何使用玩笑来模拟react-router-dom的BrowserRouter

3 个答案: