Question

我有一个XML字符串作为输入，如下所示。对于每个问题，都有多种选择。如何获得每个问题的最高分数？

谢谢。

<root>
 <Q>
 <QID>1</QID>
 <Ans>
  <Score>1</Score>
  <Choice>Choice 1</Choice>
 </Ans>
 <Ans>
  <Score>2</Score>
  <Choice>Choice 2</Choice>
 </Ans>
 <Ans>
  <Score>3</Score>
  <Choice>Choice 3</Choice>
 </Ans>
 </Q>
 <Q>
 <QID>2</QID>
 <Ans>
  <Score>10</Score>
  <Choice>Choice A</Choice>
 </Ans>
 <Ans>
  <Score>20</Score>
  <Choice>Choice B</Choice>
 </Ans>
 <Ans>
  <Score>30</Score>
  <Choice>Choice C</Choice>
 </Ans>   
 </Q>
</root>

Answer 1

如果要计算每个问题的最高分数，可以使用地图：键是问题ID，值是问题最高分数：

Map<Integer, Double> scoreMap = new HashMap<>();

然后，您只需要进行两次迭代，其中外部一个用于问题，而内部一个用于选择和评分：

Map<Integer, Double> scoreMap = new HashMap<>();
XPath xpath = XPathFactory.newInstance().newXPath();
NodeList questions = (NodeList) xpath.evaluate("/root/Q", document, XPathConstants.NODESET);
for (int i = 0; i < questions.getLength(); i++) {
  Node question = questions.item(i);
  int questionId = Integer.parseInt(xpath.evaluate("QID", question));
  System.out.println("question: " + questionId);
  NodeList answers = (NodeList) xpath.evaluate("Ans/Score", question, XPathConstants.NODESET);
  double maxScore = 0;
  for (int j = 0; j < answers.getLength(); j++) {
    System.out.println("score: " + answers.item(j).getTextContent());
    double score = Double.parseDouble(answers.item(i).getTextContent());
    maxScore = Math.max(score, maxScore);
  }
  scoreMap.put(questionId, maxScore);
}
scoreMap.forEach((k, v) -> System.out.println(k + ": " + v));

它打印：

question: 1
score: 1
score: 2
score: 3
question: 2
score: 10
score: 20
score: 30
1: 1.0
2: 20.0

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