Question

我有一个用户结构：

type User struct {
    gorm.Model
    Email         string
    Password      string
    AccountType   int
    CompanyId     int
    FirstName     string
    LastName      string
    PhoneNumber   string
    RecoveryEmail string
    Contractor    bool `gorm:"sql:'not null' default:'false'"`
}

我正在使用此结构通过gorm从数据库中获取一行：

// Get a specific user from the database.
func getUser(id uint) (*User, error) {

    var user User

    if err := database.Connection.Select("id, created_at, email, account_type, company_id, first_name, last_name").Where("id = ? ", id).First(&user).Error; err != nil {
        return nil, err
    }

    fmt.Println(&user)
    return &user, nil
}

我的杜松子酒：

// @Summary Attempts to get a existing user by id
// @tags users
// @Router /api/users/getUserById [get]
func HandleGetUserById(c *gin.Context) {
    // Were using delete params as it shares the same interface.
    var json deleteParams

    if err := c.Bind(&json); err != nil {
        c.JSON(http.StatusBadRequest, gin.H{"message": "No user ID found, please try again."})
        return
    }

    outcome, err := getUser(json.Id)

    if err != nil {
        c.JSON(http.StatusInternalServerError, gin.H{"message": "Something went wrong while trying to process that, please try again.", "error": err.Error()})
        log.Println(err)
        return
    }

    c.JSON(http.StatusOK, gin.H{
        "message": "Successfully found user",
        "user":    outcome,
    })

}

它可以很好地返回所有内容，但是当我返回&user时，未选择的字段将使用默认值返回：

{
    "message": "Successfully found user",
    "user": {
        "ID": 53,
        "CreatedAt": "2018-06-24T00:05:49.761736+01:00",
        "UpdatedAt": "0001-01-01T00:00:00Z",
        "DeletedAt": null,
        "Email": "jack@jackner.com",
        "Password": "",
        "AccountType": 0,
        "CompanyId": 2,
        "FirstName": "",
        "LastName": "",
        "PhoneNumber": "",
        "RecoveryEmail": "",
        "Contractor": false
    }
}

是否有办法从对象中删除空或空属性？还是我必须发回一个对象，并将其值映射到所述新对象？如果有一种简单的方法可以使用辅助函数来完成前者，那么我想知道如何做。

Answer 1

您可以在对象的字段定义中指定omitempty标签。

示例：

Email string `json:",omitempty"`

如果以这种方式定义字段，则JSON输出中将不会出现空值：

https://golang.org/pkg/encoding/json/#Marshal

“ omitempty”选项指定，如果字段具有空值（定义为false，0，nil指针，nil接口值以及任何空数组，slice，map，或字符串。

如何从对象中删除属性

1 个答案: