Question

我是第一次使用FLAUI和自动化测试，并想用它来测试我的系统。目前，我正在使用Thread.Sleep（）等待应用程序启动，然后找到“登录”文本框。有没有比Thread.Sleep（）更有效的方法呢？

此刻，我启动应用程序并使用Thread.sleep（10000）等待应用程序完全启动，并且在单击控件以输入密码以输入应用程序之前，可找到登录文本框。但是我知道Thread.Sleep是告诉系统等待的最差方法，尤其是在自动化测试中。有人可以提供我可以测试的其他任何东西吗？

Answer 1

始终最好使用Retry机制，并等待直到主窗口加载和控件可见。例如，调用Application.Launch之后，您最多可以重试30秒以找到主窗口，然后在其中登录

：

        Retry.WhileException(() =>
        {
            using (var automation = new UIA3Automation())
            {
                Window mainWindow = Application.GetMainWindow(automation, TimeSpan.FromSeconds(60));

                Assert.IsNotNull(Mainwindow, "Main window is not found");

                TextBox loginTextBox = mainWindow.FindFirstDescendant(x => x.ByAutomationId("txtLogin")).AsTextBox();

                Assert.IsNotNull(loginTextBox, "txtLogin is not found");
            }

        }, TimeSpan.FromSeconds(30), null, true);

Answer 2

private void RunProc()
{
Process.Start("exeName");
}


public async Task StartProcessAsync()
{
var result= await Task.Run(()=>RunProc());
//optional
Task.Delay(new TimeSpan.FromSeconds(5));
}

Answer 3

问题已经有了很好的答案，但是我发现了另一种使用FlaUI.Core.Tools.Retry类中的Retry类等待任何元素（包括主窗口）的方法

[TestFixture]
public class SmokeTests
{
    private Application _theApp;
    private UIA3Automation _automation;
    private Window _mainWindow;
    private const int BigWaitTimeout = 3000;
    private const int SmallWaitTimeout = 1000;

    [SetUp]
    public void Setup()
    {
        _theApp = FlaUI.Core.Application.Launch(new ProcessStartInfo("YOUR_APPLICATION.exe", "/quickStart"));
        _automation = new UIA3Automation();
        _mainWindow = _theApp.GetMainWindow(_automation);
    }

    [TearDown]
    public void Teardown()
    {
        _automation?.Dispose();
        _theApp?.Close();
    }

    [Test]
    public void Foo()
    {
        // This will wait until the element is available, or timeout passed
        var examplesWrapPanel = WaitForElement(() => _mainWindow.FindFirstDescendant(cf => cf.ByAutomationId("ExamplesWrapPanel")));

        // This will wait for the child element or timeout 
        var exampleButton = WaitForElement(() => examplesWrapPanel?.FindFirstDescendant(cf => cf.ByAutomationId("Another Automation Id")).AsButton());

        // Do something with your elements 
        exampleButton?.WaitUntilClickable();
        exampleButton?.Invoke();
    }

    private T WaitForElement<T>(Func<T> getter)
    {
        var retry = Retry.WhileNull<T>(
            () => getter(),
            TimeSpan.FromMilliseconds(BigWaitTimeout));

        if (!retry.Success)
        {
            Assert.Fail("Failed to get an element within a wait timeout");
        }

        return retry.Result;
    }
}

}

Answer 4

您尝试过this解决方案吗？

public static void LaunchApplication(string exePath, string arguments, bool waitForExit, bool waitForStart, int waitForStartTimeout)
    {
        ProcessStartInfo thisProcessInfo = new ProcessStartInfo();
        thisProcessInfo.CreateNoWindow = true;
        thisProcessInfo.UseShellExecute = false;
        thisProcessInfo.RedirectStandardOutput = false;
        thisProcessInfo.FileName = exePath;
        thisProcessInfo.Arguments = arguments;
        using(Process thisProcess = Process.Start(thisProcessInfo))
        {
            if(waitForStart)
                thisProcess.WaitForInputIdle(waitForStartTimeout);
            if(waitForExit)
                thisProcess.WaitForExit();
        }
    }

等待应用程序启动，而无需使用FLAUI使用Thread.Sleep（）

4 个答案: