Question

我在Oracle中有RAW（16）PK列，并尝试使用JDBC插入其中：

        PreparedStatement stmt = connection.prepareStatement("insert into COUNTRY (id, state, version, code, name, nationality, issuing_entity, country) values (?, ?, ?, ?, ?, ?, ?, ?)");
        UUID id = UUID.randomUUID();
        stmt.setObject(1, id, Types.BINARY);

但是，我遇到一个例外：

java.sql.SQLException: Invalid column type
at oracle.jdbc.driver.OraclePreparedStatement.setObjectCritical(OraclePreparedStatement.java:8494)
at oracle.jdbc.driver.OraclePreparedStatement.setObjectInternal(OraclePreparedStatement.java:7995)
at oracle.jdbc.driver.OraclePreparedStatement.setObject(OraclePreparedStatement.java:8559)
at oracle.jdbc.driver.OraclePreparedStatementWrapper.setObject(OraclePreparedStatementWrapper.java:225)
at com.zaxxer.hikari.pool.HikariProxyPreparedStatement.setObject(HikariProxyPreparedStatement.java)
at rw.gov.dgie.framework.test.AbstractTestCaseWithDB.tryToInsertCountry(AbstractTestCaseWithDB.java:78)
at rw.gov.dgie.framework.test.AbstractTestCaseWithDB.dbSetup(AbstractTestCaseWithDB.java:62)
at test.rw.gov.dgie.bms.terr.service.TestCountryService.init(TestCountryService.java:37)

当尝试使用DbSetup插入测试数据时，我遇到了相同的异常。

有没有办法让JDBC将UUID插入RAW（16）列？

我正在使用Oracle JDBC 12.2.0.1.0。

Answer 1

您必须将UUID转换为字节数组。请参见方法asBytes的用法。

在绑定之后，就像使用setBytes一样简单。

示例

def stmt = con.prepareStatement("insert into TAB_UUID (id, uuid) values (?,?)") 
// bind
stmt.setInt(1,1)
def uuid = UUID.randomUUID()
stmt.setBytes(2,asBytes(uuid)) 
def rowCount = stmt.executeUpdate()

在这种情况下，链接无法正常工作时，将UUID转换为字节数组的方法

  public static byte[] asBytes(UUID uuid) {
    ByteBuffer bb = ByteBuffer.wrap(new byte[16]);
    bb.putLong(uuid.getMostSignificantBits());
    bb.putLong(uuid.getLeastSignificantBits());
    return bb.array();
  }

Answer 2

Oracle没有真正的UUID数据类型，处理RAW(16)实际上是PITA。

我们要做的是将UUID作为字符串传递给使用hextoraw()的SQL语句：

String sql = "insert into foo (id) values (hextoraw(?))";
PreparedStatement pstmt = connection.prepareStatement(sql);
UUID uid = UUID.randomUUID();
pstmt.setString(1, uid.toString().replaceAll("-", ""));

Answer 3

我建议您将UUID的字符串版本保存为demo，并使用setString：

  uuid = UUIDFactory.getInstance().newUUID();
  pstmt.setString(1, uuid.toString());

Answer 4

private byte[] uuidToBytes(final UUID uuid) {
        if (Objects.isNull(uuid)) {
            return null;
        }

        final byte[] uuidAsBytes = new byte[16];

        ByteBuffer.wrap(uuidAsBytes)
                  .order(ByteOrder.BIG_ENDIAN)
                  .putLong(uuid.getMostSignificantBits())
                  .putLong(uuid.getLeastSignificantBits());

        return uuidAsBytes;
    }

这是将UUID类型转换为字节的辅助方法。

import Sequelize from 'sequelize'

export default class Product extends Sequelize.Model {

    // model init
    static init(sequelize) {
        return super.init({
                name: { type: Sequelize.STRING(128), allowNull: false },
                description: { type: Sequelize.TEXT, allowNull: false }
            },
            {
                sequelize,
                tableName: 'c_products'
            })
    }

    setShooter() {
        console.log('Hello World!')
    }

}

Oracle JDBC：如何将UUID插入RAW（16）列

4 个答案: