试图限制每行... 在我的查询中,我正在获取结果和用于结果的图像,但是如果存在例如: 会员有2张图片,它将显示2张图片,如果ttimages有30张照片,则将显示30张图片等
我要达到的结果是每个结果一个极限... 用一张图片而不是x的数量显示表中的一个结果,导致图像表中有多少张图片。
这是SQL ...
$sql = "
SELECT DISTINCT members.lastlogin as timeline_date, members.memusername as
timeline_title, members.town as timeline_body, memberimages.images as
timeline_img FROM members JOIN memberimages ON members.memid =
memberimages.memid
UNION ALL
SELECT DISTINCT ttages.dateadded as timeline_date, ttages.title as
timeline_title, ttages.body as timeline_body, ttages_images.image as
timeline_img FROM ttages JOIN ttages_images ON ttages.agesid =
ttages_images.ageid
UNION ALL
SELECT DISTINCT sellit_listings.dateadded as timeline_date,
sellit_listings.sittitlename as timeline_title, sellit_listings.sitcontent as
timeline_body, sellit_images.images as timeline_img FROM sellit_listings JOIN
sellit_images ON sellit_listings.listid = sellit_images.listid
UNION ALL
SELECT DISTINCT property_listings.dateadded as timeline_date,
property_listings.paddress as timeline_title, property_listings.plistdiscript
as timeline_body, property_images.image as timeline_img FROM
property_listings JOIN property_images ON property_listings.propid =
property_images.propid
UNION ALL
SELECT DISTINCT event_listings.dateadded as timeline_date,
event_listings.eventtitle as timeline_title, event_listings.eventdescript as
timeline_body, event_images.image as timeline_img FROM event_listings JOIN
event_images ON event_listings.eventid = event_images.eventid
ORDER BY timeline_date DESC LIMIT 70";
答案 0 :(得分:1)
如果您希望每个成员,年龄等一个结果行,则按它们分组:
SELECT
m.lastlogin as timeline_date,
m.memusername as timeline_title,
m.town as timeline_body,
MIN(mi.images) as timeline_img
FROM members m
JOIN memberimages mi ON m.memid = mi.memid
GROUP BY m.memid
UNION ALL
...
这是标准的SQL。不过,某些DBMS可能需要在所有列上使用伪聚合函数(即MIN(m.lastlogin)
而不是m.lastlogin
等),或将它们放在GROUP BY子句中。