Question

我有三个数组，其中的数据如下所示。

client = [{id: 1, name: client 1}, {id: 2, name: client 2}];

company = [{id: 1, name: company 1}, {id: 2, name: company 2}];

case = [{id: 1, client: 1, company: 2, name: case 1}, 
        {id: 2, client: 1, company: 1, name: case 2}];

在我看来，我需要将其显示为

客户：客户1公司：公司2案例：案例
客户：客户1公司：公司1案例：案例2

我该如何实现？我的基本要求是将case数组ID替换为相关数组的名称。我是angular的新手，使用的是angular4。在此先感谢。

Answer 1

使用forech和find一起创建一个新数组。

   clients = [{id: 1, name: 'client 1'}, {id: 2, name: 'client 2'}];
  companies = [{id: 1, name: 'company 1'}, {id: 2, name: 'company 2'}];

  case: any[] = [{id: 1, client: 1, company: 2, name: 'case 1'}, 
        {id: 2, client: 1, company: 1, name:'case 2'}];
  custom = [];

  constructor(){
    this.case.forEach((item) => {
      let company =  this.companies.find((c) => c.id === item.company)
      let client =  this.clients.find((c) => c.id === item.client)
      this.custom.push({
        id : item.id,
        company: (company) ? company.name : null,
        client: (client) ? client.name : null,
        name: item.name
      })
    })
  }

Demo

Answer 2

由于您的联接表为[Route("getprofile/{id:guid}")] public async Task<Profile> GetProfile(string id) { ... }，因此可以对其进行迭代并使用reduce在表中创建一个新数组：

case

编辑为此，您甚至可以通过扩展来减少代码：

const clients = [{id: 1, name: 'client 1'}, {id: 2, name: 'client 2'}];
const companies = [{id: 1, name: 'company 1'}, {id: 2, name: 'company 2'}];
const cases = [{id: 1, client: 1, company: 2, name: 'case 1'}, {id: 2, client: 1, company: 1, name: 'case 2'}];

const joined = cases.reduce((p ,n) => {
  p.push({
    client: clients.find(c => c.id === n.client).name,
    company: companies.find(c => c.id === n.company).name,
    case: n.name
  });
  return p;
}, []);

console.log(joined);

如何用Angular 4中另一个数组中与该ID相关的名称替换数组中的ID

2 个答案: