Question

这是我的数组，我需要按部门分组。这里的dept是一个数组，因此我需要按其dept值进行分组。

myArray = [
{name: "one", dept: ["red", "blue"]},
{name: "two", dept: ["green", "blue"]}
]

我尝试使用此代码，但无法获得所需的内容。

let deptObj = {};
_.map(myArray , el => {
  const mySubArray= [];
  _.filter(el.dept, (depts, i) => {            
     mySubArray.push(el.member);
     deptObj[depts] = mySubArray;
  })
}
});

我需要这样的结果，有人可以帮助我吗？

deptObj={
red:[
    {name: "one", dept:["red", "blue"]}
],
blue:[
    {name: "one", dept:["red", "blue"]},
    {name: "two", dept:["green", "blue"]}
],
green:[
    {name: "two", dept:["green", "blue"]}
]
}

Answer 1

此解决方案可以满足您的需求：

limit 36

Answer 2

您可以使用Array.reduce()：

var arr = [
  {name: "one", dept: ["red", "blue"]},
  {name: "two", dept: ["green", "blue"]}
];

var result = arr.reduce((a,curr)=>{
    curr.dept.forEach((e)=>{ (a[e] = (a[e] || [])).push(curr)});
    return a;
},{});
console.log(JSON.parse(JSON.stringify(result)));

Answer 3

有趣的问题。这是另一个解决方案，它是“一个衬套”，并使用 .reduce / .map / _。concat

：

const arr = [{name: "one", dept: ["red", "blue"]},{name: "two", dept: ["green", "blue"]}]

var result = arr.reduce((r, {dept}, i, a) => dept.map(x => r[x] = _.concat(r[x] || [], [a[i]])) && r, {})

console.log(result)

需要按多个选定值数组分组

3 个答案: