我知道这个问题已经被问过很多次了,但是每次遇到未定义的变量时,我都会停留在某个地方以获取数据。有人可以帮助使用jquery ajax遍历JSON数据吗?
[
{
"Orderdetails":[
{
"errorMsg":"success",
"customername":"Walk In Customer",
"grandtotal":"1496.00",
"outletname":"Pradhan Ji Mobile",
"paymentmethodname":"Cash",
"customer_id":"1",
"outlet_id":"13"
}
]
},
{
"product":[
{
"product_name":"Tripr Printed Men V-neck Multicolor T-Shirt",
"product_code":"5674664",
"price":"374.00",
"qty":"2"
},
{
"product_name":"Tripr Printed Men V-neck Multicolor T-Shirt",
"product_code":"5674665",
"price":"374.00",
"qty":"1"
},
{
"product_name":"Tripr Printed Men V-neck Multicolor T-Shirt",
"product_code":"5674666",
"price":"374.00",
"qty":"1"
}
]
}
]
提前谢谢。
答案 0 :(得分:2)
如果您想获取customer_id的意思,请尝试data[0].Orderdetails[0].customer_id
数据将为JSON。
答案 1 :(得分:1)
您获得的对象是2个对象Orderdetails
和product
的列表,它们都包含另一个列表。如果要从customer_id
中提取Orderdetails
,可以按以下步骤进行。
// let's assume the list is called jsonList.
// Orderdetails is an element of the first list
const orderdetails = jsonList[0].Orderdetails;
// Then get the customer_id out of the first list in Orderdetails
const customer_id = Orderdetails[0].customer_id;
或者以较短的方式完成所有这些操作
const customer_id = jsonList[0].Orderdetails[0].customer_id;
编辑
如果要遍历product
,请使用.forEach()
// get the list product
const product = jsonList[0].product;
// iterate through it with forEach()
product.forEach( element => {
// you now have access to the fields of each single element of the list
console.log('product_name', element.product_name);
console.log('product_code', element.product_code);
// .. and so on
});