Question

对不起-希望您不要介意我问这个问题，但是我是SQL的新手-有人可以对这段代码在代码中的含义进行评论吗？

select b.recipeuuid
      ,b.proditemuuid
      ,b.proditemvalueuuid
  into #rectemp
  from rec_recipe as a
       inner join rec_recipevalue as b
               on b.recipeuuid=a.recipeuuid
              and b.[value] in ('Green','Yellow')
       inner join rec_proditem as c
               on c.proditemuuid=b.proditemuuid
       inner join rec_proditemvalue as d
               on d.proditemuuid=c.proditemuuid
              and d.proditemvalueuuid=b.proditemvalueuuid
              and d.[name]='SetupType'
;

update a
   set a.[value]='1'
  from rec_recipevalue as a
       inner join #rectemp as b
               on b.recipeuuid=a.recipeuuid
              and b.proditemuuid=a.proditemuuid
              and b.proditemvalueuuid=a.proditemvalueuuid
 where a.[value] in ('Green','Yellow')
;

update a
   set a.[name]='Normal'
  from rec_proditemvalue as a
       inner join #rectemp as b
               on b.proditemuuid=a.proditemuuid
              and b.proditemvalueuuid=a.proditemvalueuuid
 where a.[name]='SetupType'
;

drop table #rectemp;

我了解这段代码的基本概念。它与如何更新（或更改）两个不同列的值有关：属性和颜色。在我使用适当的UUID将它们加入之前，这两个项目位于两个不同的表中。仅当Attribute =“ SetupType”和Color =“ Green”或“ Yellow”

时，更新才可以放置

我想将这两个值更改为：

Attribute ='Normal'和颜色=“ 1”

Answer 1

SelectedItems

代码说明-请

1 个答案: