分组条形图：ggplot

Question

我有以下数据。

我要做的是首先对列Feature1，Feature2和Feature3进行排序和匹配，以使其与第一列Feature的顺序相同，他们相应的数字。

Feature对应于LastYear

Feature1对应于OneYear

Feature2对应于TwoYear

Feature3对应于ThreeYear

因此，使用Feature1及其对应的OneYear列，由于logTA = 0.32627....位于{{1}中，因此row 2的值将下降到logTA } row 2列中。 Feature会降为CA.CL = 0.16196....等。

row 6和Feature 2同样适用。全部根据与Feature 3列的匹配进行排序。

******也许不需要上面的部分。

第二，我想Feature数据帧，按melt，LastYear，OneYear和TwoYear分组。

所以想法是要绘制类似于以下内容的东西；

其中ThreeYear，Food和Music将被People，LastYear，OneYear和TwoYear取代。这些条也将对应于ThreeYear，CA.CL等。

logTA

编辑：

structure(list(Feature = structure(c(6L, 8L, 5L, 11L, 4L, 1L, 
3L, 2L, 7L, 10L, 9L), .Label = c("CA.CL", "CA.TA", "CF.NCL", 
"CL.FinExp", "DailySALES.EBIT", "EBIT.FinExp", "EQ.Turnover", 
"logTA", "SALES.WC", "TL.EQ", "TL.TA"), class = "factor"), LastYear = structure(c(11L, 
10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 2L, 1L), .Label = c("0.0322326139141556", 
"0.0418476895487213", "0.0432506289654195", "0.0504153839825875", 
"0.0546743268879608", "0.0549979876321639", "0.0577181189006888", 
"0.107473282590142", "0.112929456881545", "0.139817111427972", 
"0.304643399268643"), class = "factor"), Feature1 = structure(c(8L, 
6L, 1L, 3L, 11L, 9L, 4L, 10L, 5L, 7L, 2L), .Label = c("CA.CL", 
"CA.TA", "CF.NCL", "CL.FinExp", "DailySALES.EBIT", "EBIT.FinExp", 
"EQ.Turnover", "logTA", "SALES.WC", "TL.EQ", "TL.TA"), class = "factor"), 
    OneYear = structure(c(11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 
    2L, 1L), .Label = c("0.0241399538457295", "0.025216904130219", 
    "0.0288943827773218", "0.0290134083108585", "0.0393919110672302", 
    "0.0484816627329215", "0.0660812827117713", "0.0728943625765924", 
    "0.161968277822423", "0.177638448005797", "0.326279406019136"
    ), class = "factor"), Feature2 = structure(c(8L, 1L, 6L, 
    9L, 11L, 3L, 2L, 5L, 4L, 10L, 7L), .Label = c("CA.CL", "CA.TA", 
    "CF.NCL", "CL.FinExp", "DailySALES.EBIT", "EBIT.FinExp", 
    "EQ.Turnover", "logTA", "SALES.WC", "TL.EQ", "TL.TA"), class = "factor"), 
    TwoYear = structure(c(11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 3L, 
    2L, 1L), .Label = c("0.0179871842234001", "0.0245082857218191", 
    "0.0276514285623367", "0.0359182021377123", "0.0461243809893583", 
    "0.046996298679094", "0.0566018025811507", "0.0648203522637183", 
    "0.0815346014308433", "0.210073355633034", "0.387784107777533"
    ), class = "factor"), Feature3 = structure(c(8L, 1L, 11L, 
    7L, 9L, 5L, 2L, 6L, 3L, 4L, 10L), .Label = c("CA.CL", "CA.TA", 
    "CF.NCL", "CL.FinExp", "DailySALES.EBIT", "EBIT.FinExp", 
    "EQ.Turnover", "logTA", "SALES.WC", "TL.EQ", "TL.TA"), class = "factor"), 
    ThreeYear = structure(c(11L, 10L, 9L, 8L, 7L, 6L, 5L, 4L, 
    3L, 2L, 1L), .Label = c("0.0275302883400183", "0.0282746857626618", 
    "0.0403110592712779", "0.0409053619122674", "0.0514576931772448", 
    "0.0570216362435987", "0.076967996046118", "0.0831531609222676", 
    "0.0904194376665785", "0.139457271733071", "0.364501408924896"
    ), class = "factor")), .Names = c("Feature", "LastYear", 
"Feature1", "OneYear", "Feature2", "TwoYear", "Feature3", "ThreeYear"
), row.names = c(NA, -11L), class = "data.frame")

Answer 1

如果您将其重新排列为长格式，则绘图非常简单。
这是使用purrr:map2()来做到这一点的方法：

library(tidyverse)

feature_suffix <- c("", "1", "2", "3")
year_prefix <- c("Last", "One", "Two", "Three")

map2(feature_suffix, year_prefix,
     ~ df %>% 
       select(feature = paste0("Feature", .x), value = paste0(.y, "Year")) %>%
       mutate(year = paste0(.y, "Year"))
) %>%
  bind_rows(.) %>%
  mutate(value = as.numeric(value)) %>%
  ggplot(aes(year, value, fill=feature)) +
  geom_bar(stat="summary", fun.y=mean, position = position_dodge(.9))