Python：单击没有链接的下一页（javascript / AJAX）

Question

我希望一个善良的灵魂可以在这里帮助我。我需要点击此网站下一页的帮助：https://www.xtip.co.uk/en/today/index.html。

我的代码：

from selenium import webdriver

url = 'https://www.xtip.co.uk/en/today/index.html'
browser = webdriver.Chrome('./Browser/chromedriver')
browser.get(url)

amount_of_pages_xpath = browser.find_element_by_xpath('//*[@id="widget_today_tabbed"]/div[2]/div[2]/div')
amount_of_pages_html = amount_of_pages_xpath.get_attribute('data-number-of-pages')

for x in range(len(amount_of_pages_html)):
    browser.find_element_by_xpath('//*[@id="widget_today_tabbed"]/div[2]/div[2]/div/ul/li[8]/a').click()

它使用JavaScript和AJAX，因此我使用Selenium，但无法使其切换页面。我究竟做错了什么？通常，当我转到Chrome->检查->复制Xpath->将此路径放入find_element_by_xpath（）并添加click（）时，此方法正常工作。

我在控制台中的错误：

  selenium.common.exceptions.WebDriverException: Message: unknown error: Element <a href="#" class="widget-page-link widget-page-link-next" data-target-page="next">...</a> is not clickable at point (917, 654). Other element would receive the click: <div class="cc_message">...</div>
          (Session info: chrome=67.0.3396.87)
          (Driver info: chromedriver=2.38.552518 (183d19265345f54ce39cbb94cf81ba5f15905011),platform=Mac OS X 10.13.5 x86_64)

Answer 1

您可以使用以下代码：

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC 

browser = webdriver.Chrome(executable_path = r'D:/Automation/chromedriver.exe')
browser.get("https://www.xtip.co.uk/en/today/index.html")

wait = WebDriverWait(browser, 30)

browser.execute_script("window.scrollTo(0, 800)") 

next_button = wait.until(EC.element_to_be_clickable((By.CSS_SELECTOR, "a.widget-page-link.widget-page-link-next")))

next_button.click()