我想找到一种简单的方法来替换JSON文件中的值。
我正在寻找类似的东西
json_file.replace("-", "")
示例:
"scores": {
"count": 1,
"my-followings": 420,
"my-plain-tweets": 0,
"my-tweets-with-links": 1,
"my-tweets-with-image": 0,
"my-replies": 0,
"my-listed": 113,
"my-retweets": 0,
"my-statuses": 3653,
"my-followers": 8536,
"favourites": 0,
"my-tweets-with-video": 0,
"my-favourites": 7929,
"retweets": 0
}
预期:
"scores": {
"count": 1,
"myfollowings": 420,
"myplaintweets": 0,
"mytweetswithlinks": 1,
"mytweetswithimage": 0,
"myreplies": 0,
"mylisted": 113,
"myretweets": 0,
"mystatuses": 3653,
"myfollowers": 8536,
"favourites": 0,
"mytweetswithvideo": 0,
"myfavourites": 7929,
"retweets": 0
}
添加了样本以及我的期望。
答案 0 :(得分:2)
使用str.replace
演示:
import json
with open(filename, "r") as infile: #Read json
data = json.load(infile)
data = dict((k.replace("-", ""), v) for k, v in data["scores"].items()) #Remove "-"
with open(filename, "w") as outfile: #Write back to file
data = json.dump({"scores": data}, outfile)
根据评论进行编辑
with open(filename, "r") as infile:
data = infile.read().replace("-", "")
with open(filename, "w") as outfile:
outfile.write(data)
答案 1 :(得分:1)
命令行工具jq是专为此类问题设计的。
例如,假设您要更改所有对象中所有键名(但仅键名)中的所有连字符, 不管嵌套有多深:
walk(if type == "object" then with_entries(.key |= gsub("-";"")) else . end)
如果您只想更改第一个连字符,则可以将gsub
更改为sub
。
如果您的jq没有walk/1
,则可以包含其定义,例如
# Apply f to composite entities recursively, and to atoms
def walk(f):
. as $in
| if type == "object" then
reduce keys_unsorted[] as $key
( {}; . + { ($key): ($in[$key] | walk(f)) } ) | f
elif type == "array" then map( walk(f) ) | f
else f
end;
walk(if type == "object" then with_entries(.key |= gsub("-";"")) else . end)
sponge
如果要覆盖输入文件,则诸如sponge
之类的实用程序将派上用场。例如,如果JSON在文件中(例如input.json),并且如果上述jq程序在program.jq中,则可以按
如下:
jq -f program.jq input.json | sponge input.json