Question

我正在努力寻找一条规则，该规则将与两组可选字符串-birthday/birth/bday/born之间的日期模式（并且仅与该模式）匹配。

输入中必须包含一个或多个字符串，然后才能匹配日期。

如果可能，还需要在单个Regex匹配操作中执行。这是我需要通过处理程序运行的几个表达式之一，该处理程序只需要一个表达式，而没有其他逻辑的便利。

这是一个例子：

I was born on 01/01-2001

应匹配 2001年1月1日

My bday was on 01-01-2001 which was the day I was born, obviously

应匹配 2001年1月1日

01 01 2001 was my day of birth

应匹配 01 01 2001

Today’s date is 24/06/2018

不匹配

到目前为止，我有：(?<=.*born|birth|bday).*?([0-9]{2,4}[^A-Za-z0-9]+[0-9]{2,4}[^A-Za-z0-9]+[0-9]{2,4})，如果这些字符串在日期之前，则可以完美地匹配日期。如果我在日期之后有这些字符串，则不匹配任何内容。

Answer 1

像这样简单的事情可以按您的意愿工作吗？

/\d\d\/\d\d\/\d\d\d\d/

堆栈片段

var nr1 = "I was born on 01/01/2001"
var nr2 = "My bday was on 01/01/2001 which was the day I was born, obviously"
var nr3 = "01/01/2001 was my day of birth"

console.log(nr1.match(/\d\d\/\d\d\/\d\d\d\d/));
console.log(nr2.match(/\d\d\/\d\d\/\d\d\d\d/));
console.log(nr3.match(/\d\d\/\d\d\/\d\d\d\d/));

根据评论进行了更新。

如果要同时检查日期{em>和这两个单词birth|bday|born，因为简单的解决方案是进行两次匹配

堆栈片段

var nr1 = "I was born on 01/01/2001"
var nr2 = "My bday was on 01/01/2001 which was the day I was born, obviously"
var nr3 = "01/01/2001 was my day of birth"
var nr4 = "This is a simple date 01/01/2001"


console.log(nr1.match(/(birth|bday|born)/) &&         
            nr1.match(/\d\d\/\d\d\/\d\d\d\d/));

console.log(nr2.match(/(birth|bday|born)/) && 
            nr2.match(/\d\d\/\d\d\/\d\d\d\d/));

console.log(nr3.match(/(birth|bday|born)/) && 
            nr3.match(/\d\d\/\d\d\/\d\d\d\d/));

console.log(nr4.match(/(birth|bday|born)/) &&
            nr4.match(/\d\d\/\d\d\/\d\d\d\d/));

根据评论第二次更新。

将两个匹配项合并到一个正则表达式中，这篇文章既显示又给出了一些出色的解释：

Regex AND operator

堆栈片段

var nr1 = "I was born on 01/01/2001"
var nr2 = "My bday was on 01/01/2001 which was the day I was born, obviously"
var nr3 = "01/01/2001 was my day of birth"
var nr4 = "This is a simple date 01/01/2001"


console.log(nr1.match(/(?=.*(birth|bday|born))(?=.*(\d\d\/\d\d\/\d\d\d\d))/));     
console.log(nr2.match(/(?=.*(birth|bday|born))(?=.*(\d\d\/\d\d\/\d\d\d\d))/));     
console.log(nr3.match(/(?=.*(birth|bday|born))(?=.*(\d\d\/\d\d\/\d\d\d\d))/));     
console.log(nr4.match(/(?=.*(birth|bday|born))(?=.*(\d\d\/\d\d\/\d\d\d\d))/));

Answer 2

您可以先测试出生，生日或出生，然后匹配一组由单个字符分隔的三个数字。

/birth|born|bday/.test(str)? str.match(/\d+.\d+.\d+/)[0] : ""

str = "I was born on 01/01-2001"
console.log(/birth|born|bday/.test(str)? str.match(/\d+.\d+.\d+/)[0] : "")

str = "01 01 2001 was my day of birth"
console.log(/birth|born|bday/.test(str)? str.match(/\d+.\d+.\d+/)[0] : "")

str = "Today’s date is 24/06/2018"
console.log(/birth|born|bday/.test(str)? str.match(/\d+.\d+.\d+/)[0] : "")

正则表达式以匹配两组可选字符串之间的模式

2 个答案: