Question

我有一个Java程序在我的Swift程序的后台运行。 Java程序可以在命令行中读取用户输入。启动后如何在jar中传递“命令”或文本行？

就像下面的程序从Java程序中读取的方式一样，然后如何“回复”呢？

    let b = Bundle.main
    let path = b.path(forResource: "myjar", ofType: "jar")!
    NSLog("%@", "jar path : \(path)")

    task.launchPath = "/usr/bin/java"
    task.arguments = ["-jar", path]
    let pipe = Pipe()
    task.standardOutput = pipe
    let errorPipe = Pipe()
    task.standardError = errorPipe
    task.launch()
    let outHandle = pipe.fileHandleForReading
    outHandle.waitForDataInBackgroundAndNotify()
    var progressObserver : NSObjectProtocol!
    progressObserver = NotificationCenter.default.addObserver(
        forName: NSNotification.Name.NSFileHandleDataAvailable,
        object: outHandle, queue: nil){

            notification -> Void in
            let data = outHandle.availableData

            if data.count > 0 {
                if let str = String(data: data, encoding: String.Encoding.utf8) {
                    NSLog("%@", str)

                }
                outHandle.waitForDataInBackgroundAndNotify()
            } else {                 NotificationCenter.default.removeObserver(progressObserver)
            }
    }

然后我尝试了以下方法而没有运气：

pipe.fileHandleForWriting.write("text to send to java program".data(using: String.Encoding.utf8)

Answer 1

您非常接近。如果您只是添加了代码<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div id="toggle-element"> <div class="wrap"> <a href="#" class="navbtns prev" title="Go to Next Page"> <svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 50 50"><path d="M25,50A25,25,0,1,0,0,25,25,25,0,0,0,25,50ZM25,2A23,23,0,1,1,2,25,23,23,0,0,1,25,2Zm-3,9V39L32,25Z" style="fill-rule:evenodd"/></svg> </a> <a href="#" class="navbtns next" title="Go to Previous Page"> <svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 50 50"><path d="M25,50A25,25,0,1,1,50,25,25,25,0,0,1,25,50ZM25,2A23,23,0,1,0,48,25,23,23,0,0,0,25,2Zm3,9V39L18,25Z" style="fill-rule:evenodd"/></svg> </a> </div> </div> <div id="container1"> Scroll down to <b>#container2</b> </div> <div id="container2"> This is <b>#container2</b> </div> <div id="container3"> Scroll up to <b>#container2</b> </div>，该代码将无法工作，因为该管道是您分配给pipe.fileHandleForWriting.write("text to send to java program"...的管道。

您需要创建另一个standardOutput对象，将其分配给Pipe，然后写入：

standardInput

快速将命令传递到jar文件

1 个答案: