Question

我正在尝试创建一个调用存储过程的方法，以进行非常简单的插入和选择，

我在Oracle数据库上创建了一个存储过程，如下所示：

CREATE OR REPLACE PROCEDURE schema.insertNewTable(p_test IN VARCHAR2, p_out OUT VARCHAR2)
IS
BEGIN
INSERT INTO NEWTABLE("TEST") VALUES(p_test);
SELECT '1' INTO p_out FROM DUAL;

COMMIT;

END;

然后在实体上

@Procedure(procedureName = "insertNewTable", outputParameterName="p_out")
String insertNewTable(@Param("p_test") String p_test);

但是每次我调用此方法时，我都会得到：

2018-06-23 20:04:43,047|ORA-06550: row 1, colonna 7:
PLS-00306: wrong number or types of arguments in call to 'INSERTNEWTABLE'
ORA-06550: riga 1, column 7:
PL/SQL: Statement ignored

2018-06-23 20:04:43,100|org.springframework.dao.InvalidDataAccessResourceUsageException: Error calling CallableStatement.getMoreResults; SQL [insertNewTable]; nested exception is org.hibernate.exception.SQLGrammarException: Error calling CallableStatement.getMoreResults
    at org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:261)
    at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible(HibernateJpaDialect.java:244)
    at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.translateExceptionIfPossible(AbstractEntityManagerFactoryBean.java:503)

经过几次尝试（和例外），我修改了Entity和调用以避免“ OUT”类型，因此，我没有错误：

CREATE OR REPLACE PROCEDURE schema.insertNewTable(p_test IN VARCHAR2)
IS
BEGIN
INSERT INTO NEWTABLE("TEST") VALUES(p_test);

COMMIT;

END;

然后在实体上

@Procedure(procedureName = "insertNewTable")
void insertNewTable(@Param("p_test") String p_test);

如何解决此问题以获得返回值？

Answer 1

您可以使用NamedStoredProcedureQuery

@NamedStoredProcedureQuery(
    name = "insertNewTable", 
    procedureName = "insertNewTable", 
    parameters = { 
        @StoredProcedureParameter(mode = ParameterMode.IN, type = String.class, name 
= "p_test"), 
        @StoredProcedureParameter(mode = ParameterMode.OUT, type = String.class, name 
= "p_out"), 
      )
    }
)

方法调用：

StoredProcedureQuery query = 
this.em.createNamedStoredProcedureQuery("insertNewTable");
query.setParameter("p_test", ""TEST"");
query.execute();
String out =  query.getOutputParameterValue("p_out");

Answer 2

使用Spring DATA

在您的存储库中：

1）使用本机SQL调用：

@Query（值=“从对偶中选择存储过程名称（：param）”，nativeQuery = true） BigDecimal method-name（@Param（“ param”）Long param）;

2）

@Procedure(procedureName = "store-procedure-name", outputParameterName = "output-param-of-store-procedure")

return-type-of-store-procedure  method-name(input-params-of-store-procedure);

Spring Data Jpa调用存储过程

2 个答案: