Question

当我试图这样写自己的decay_t时：

#include <utility>
template <class T>
struct auto_decay {
    auto operator () () noexcept {
        return std::declval<T>();
    }
};

template <class T> using decay_t = decltype( (decl_as<decay_impl::auto_decay< T >>())() );

并使用以下命令进行测试：

#include <type_traits>
int main() {
    static_assert(is_same<decay_t<int ()&>, int (*)()>{}());
}

我遇到以下错误：

In file included from test_decay.cc:1:
In file included from ./../src/decay.hpp:4:
In file included from ./../src/utility.hpp:3:
./../src/add_reference.hpp:17:14: error: reference to function type 'int () &' cannot have '&' qualifier
    typedef T&& type;
             ^
./../src/add_reference.hpp:20:1: note: in instantiation of template class 'nxwheels::concept_check::add_rvalue_reference<int () &>' requested here
using add_rvalue_reference_t = typename add_rvalue_reference<T>::type;
^
./../src/utility.hpp:14:1: note: in instantiation of template type alias 'add_rvalue_reference_t' requested here
auto declval() noexcept -> add_rvalue_reference_t<T>;
^
./../src/decay.hpp:10:16: note: while substituting explicitly-specified template arguments into function template 'declval' 
        return declval<T>();
               ^
./../src/decay.hpp:16:46: note: in instantiation of member function 'nxwheels::concept_check::decay_impl::auto_decay<int () &>::operator()' requested here
template <class T> using decay_t = decltype( (decl_as<decay_impl::auto_decay< T >>())() );
                                             ^
test_decay.cc:17:17: note: in instantiation of template type alias 'decay_t' requested here
    assert_same<decay_t<int (void)&>, int (*)(void)>();
                ^
In file included from test_decay.cc:1:
./../src/decay.hpp:10:16: error: call to function 'declval' that is neither visible in the template definition nor found by argument-dependent lookup
        return declval<T>();
               ^
./../src/decay.hpp:16:46: note: in instantiation of member function 'nxwheels::concept_check::decay_impl::auto_decay<int () &>::operator()' requested here
template <class T> using decay_t = decltype( (decl_as<decay_impl::auto_decay< T >>())() );
                                             ^
test_decay.cc:17:17: note: in instantiation of template type alias 'decay_t' requested here
    assert_same<decay_t<int (void)&>, int (*)(void)>();
                ^
./../src/utility.hpp:14:6: note: 'declval' should be declared prior to the call site
auto declval() noexcept -> add_rvalue_reference_t<T>;
     ^
In file included from test_decay.cc:2:
./../src/concepts/is_same.hpp:18:5: error: static_assert failed
    static_assert(is_same_v<T1, T2>);
    ^             ~~~~~~~~~~~~~~~~~
test_decay.cc:17:5: note: in instantiation of function template specialization 'nxwheels::concept_check::assert_same<int, int (*)()>' requested here
    assert_same<decay_t<int (void)&>, int (*)(void)>();
    ^
3 errors generated.

为什么不能将&&添加到Ret (Args...) &？

Answer 1

int () &并不是您（似乎）认为的那样。

它不是对函数的引用，而是对ref-qualified函数的引用。

如果要引用功能，则需要使用int (&)()。

为什么我不能将&&添加到Ret (Args...) &

似乎合格的（ref-或cv合格的）函数类型只能在非常特定的地方使用：

[dcl.typedef]/6

具有 cv-qualifier-seq 或 ref-qualifier 的函数类型（包括以typedef-name（[dcl.typedef]，{{ 1}}））   仅显示为：

-非静态成员的函数类型   功能

-指向成员的指针所指向的函数类型，

-函数typedef声明的顶级函数类型或   别名声明

- type-parameter 的默认参数中的 type-id ，或

- type-parameter （[temp.param]）的 template-argument 的 type-id 。

为什么我不能将&&添加到Ret（Args ...）＆？

1 个答案:

[dcl.typedef]/6