Question

我有一个数据框，如下所示：

from uncertainties import ufloat # pip3 uncertainties.py 
import random
random.seed(0)
values = [[round(random.random(),2) for i in range(3)] for j in range(4)]
df = pd.DataFrame(values, index=['name1','sd', 'name2', 'sd'], columns=['A','B','C'])

我想重新排列数据，将均值和sd合并为ufloat的一行，其预期输出如下：

new_values = [[ufloat(0.91,0.90), ufloat(0.98,0.31), ufloat(0.81,0.73)],
             [ufloat(0.90,0.10), ufloat(0.68,0.43), ufloat(0.47, 0.61)]]
df = pd.DataFrame(new_values, index=['name1', 'name2'], columns=['A','B','C'])

我认为创建两个数据框并以某种方式将它们组合起来最简单

mean = df.iloc[::2].reset_index()
std  = df.iloc[1::2].reset_index()

现在我需要将两者合并并应用ufloat

Answer 1

这是我当前的解决方案：

    auto it = std::find_if(sourceEmployee.begin(), sourceEmployee.end(),
                      [&sourceEmployee, id](const auto &obj) { return obj->getID() == id; });
    auto index = std::distance(sourceEmployee.begin(), it);

        switch(sourceEmployee[index]->getStatus()) { // returning status

            case Intern::Status::Intern: // does it recognize object properly?

                auto tmp0 = std::move(*it);
                (*it).reset();                         // ??
                *it = std::make_shared<Worker>(tmp0);

                cout << "Employee " << id << " has been promoted" << endl;
                break;

大熊猫操作每两行结合

1 个答案: