要求 FormStateModel已经包含用户键入的FIRST输入。
代码 我只想将 activity.Text 中的字符串放在FormStateModel内:
private IDialog<FormStateModel> MakeRootDialog(string input)
{
return Chain.From(() => new FormDialog<FormStateModel>(
new FormStateModel() { Question = input },
ContactDetailsForm.BuildForm,
FormOptions.None));
}
=
public async Task<HttpResponseMessage> Post([FromBody] Activity activity)
{
if (activity.Type == ActivityTypes.Message)
{
await Conversation.SendAsync(
toBot: activity,
MakeRoot: () => this.MakeRootDialog(activity.Text));
}
else
{
await HandleSystemMessageAsync(activity);
}
var response = this.Request.CreateResponse(HttpStatusCode.OK);
return response;
}
在ConversationUpdate上,我只需问“请输入您的问题:”即可开始对话。
private static async Task<Activity> HandleSystemMessageAsync(Activity message)
{
switch (message.Type)
{
case ActivityTypes.DeleteUserData:
break;
case ActivityTypes.ConversationUpdate:
await Welcome(message);
break;
(...)
以这种方式:
private static async Task Welcome(Activity activity)
{
(...)
reply.Text = string.Format("Hello, how can we help you today? Please type your Question:");
await client.Conversations.ReplyToActivityAsync(reply);
(...)
}
但是我找不到一种方法来传递它。在这种情况下,会发生此异常:
anonymous method closures that capture the environment are not serializable, consider removing environment capture or using a reflection serialization surrogate:
在这一步周围有什么方法可以填充状态模型吗?
答案 0 :(得分:4)
通过在MessagesController中调用RootDialog,然后通过context.Call(form,(...));
public async Task<HttpResponseMessage> Post([FromBody] Activity activity)
{
await Conversation.SendAsync(activity, () => new LayerDialog());
}
LayerDialog:
[Serializable]
public class LayerDialog: IDialog<IMessageActivity>
{
public async Task StartAsync(IDialogContext context)
{
context.Wait(this.OnMessageReceivedAsync);
}
private async Task OnMessageReceivedAsync(IDialogContext context, IAwaitable<IMessageActivity> result)
{
var awaited = await result;
FormStateModel model = new FormStateModel();
model.Value = awaited.Text;
var form = new FormDialog<FormStateModel >(model ,
BuildForm , FormOptions.PromptInStart);
context.Call(form , this.AfterResume);
}