Question

您好，请您帮我解决阵列中的重复项。

public class main {
    public static void main(String[] args) {
        String [] arr = {"Barcelona","Watford","Manchester United","Real Mandrid","Barcelona","Machester United","city"};
        int[] arraya = { 1, 2, 3, 4, 2, 3, 1,11 }; // input array
        int L = arr.length;

        for (int i = 0; i < L; i++) {
            System.out.print("  " + arr[i]);
        }
        System.out.println("\n" );

        for (int i = 0; i < (L- 1) ; i++) {
            for (int j = i + 1; j < L; j++) {
                if(arr[i].equals(arr[j]));{
                    arr[j] = arr[L -1];
                    L--;
                }
            }
        }

        for (int i = 0; i < L; i++) {
            System.out.print("  " + arr[i]);
        }
    }
}

我没有得到预期的答案，数组也删除了唯一值。

Answer 1

您可以使用Set，它将删除重复项。要将数组转换为set，只需使用以下命令：

Set<String> mySet = new HashSet<>(Arrays.asList(arr));

Answer 2

在此;之后，您还有if(arr[i].equals(arr[j]))吗？我认为，如果删除它，您的问题就可以解决。

Answer 3

public class main {
    public static void main(String[] args) {
        String [] arr = {"Barcelona","Watford","Manchester United","Real Mandrid","Barcelona","Manchester United","city"};
        int L = arr.length;

        for (int i = 0; i < L; i++){
            System.out.print(" " + arr[i]);
        }
        System.out.println();     

        for (int i = 0; i < L - 1 ; i++) {
            for (int j = i + 1; j < L; j++) {
                if(arr[i].equals(arr[j])){
                    arr[j] = arr[L -1];
                    L--;
                    j--;
                }
            }
        }

        for (int i = 0; i < L; i++){
            System.out.print(" " + arr[i]);
        }
        System.out.println();   
    }
}

结果：

Barcelona Watford Manchester United Real Mandrid Barcelona Manchester United city
Barcelona Watford Manchester United Real Mandrid city

不使用方法删除数组重复项

3 个答案: