如何将编译器标志传递给Rust中的子板条箱？

Question

我有A和B的板条箱。 A取决于B，并且B具有名为some_feature的功能。

我可以通过运行B来使用货运来构建cargo build --features=some_feature，但是如何为A设置相同的功能，我可以选择为基础启用或禁用some_feature编译B时将A放在箱子里吗？

Answer 1

您可以简单地转发A中指定的功能：

# A/Cargo.toml

[features]
some-feature = ["B/some-feature"]

[dependencies]
B = "*"

如果您将B传递给--features=some_feature，它将用--features=some_feature编译A。

Answer 2

您只需要配置清单，就像doc这样简单：

[dependencies.awesome]
version = "1.3.5"
default-features = false # do not include the default features, and optionally
                         # cherry-pick individual features
features = ["secure-password", "civet"]