按SQL中的总数计数

Question

我的表结构如下

现在，我的要求是我需要查询交易最多的供应商

SELECT vendor_id,COUNT(deal_id) AS total_dealid 
FROM `user_downloaded_deals` 
GROUP BY `vendor_id`

但是它按vendor_id顺序返回数据，而我需要按total_dealid ORDER来返回数据。表示下载最多的供应商的交易首先显示 例如当前的o / p是

vendor_id   total_dealid
1           3
2           2
5           5

预期O / p

vendor_id   total_dealid
5           5
1           3
2           2

Answer 1

尝试此查询

SELECT vendor_id,COUNT(deal_id) AS total_dealid 
FROM `user_downloaded_deals` 
GROUP BY `vendor_id` ORDER BY total_dealid DESC

Answer 2

使用此查询

SELECT vendor_id,COUNT(deal_id) AS total_dealid FROM user_downloaded_deals 
 GROUP BY vendor_id order by total_dealid desc

没有“排序依据”

Answer 3

排序依据也可以与别名一起使用，因此查询如下：

SELECT vendor_id, COUNT(deal_id) AS total_dealid FROM `user_downloaded_deals` 
    GROUP BY `vendor_id` ORDER BY total_dealid DESC

Answer 4

您无法在total_dealid前下订单。在SQL中，无法按别名列进行排序。相反，您必须重复您的订单对帐单。以下应该可以解决您的问题。

SELECT vendor_id,COUNT(deal_id) AS total_dealid 
FROM `user_downloaded_deals` 
GROUP BY `vendor_id`
ORDER BY count(deal_id) DESC;

编辑：较新的SQL版本允许使用别名列进行排序，因此这也应该起作用：

SELECT vendor_id,COUNT(deal_id) AS total_dealid 
FROM `user_downloaded_deals` 
GROUP BY `vendor_id`
ORDER BY total_dealid DESC;

Answer 5

您可以按total_dealid或count（deal_id）desc添加订单

SELECT vendor_id,COUNT(deal_id) AS total_dealid 
FROM `user_downloaded_deals` 
GROUP BY `vendor_id` order by total_dealid  Desc