Question

df_devices = df.groupby(['from_time', 'device', 'type'])['power'].mean()

在计算列中mean()的{{1}}之后，我得到了一个包含以下内容的熊猫系列

groupby

我想将其转换为以下格式的字典：

from_time  device         type   
00:00:00   AC             indoor     1362.214286
                          outdoor    3470.705882
           Computer       indoor      399.000000
                          outdoor     412.400000
           Heater         indoor     2258.375000
                          outdoor    2274.666667
           Lights         indoor     1535.000000
                          outdoor    3475.473684
           Microwave      indoor     1420.000000
                          outdoor    1489.933333
           Refridgerator  indoor      192.388889
                          outdoor     195.076923
           Television     indoor      243.666667
                          outdoor     261.500000
01:00:00   AC             indoor     1493.071429
                          outdoor    3724.352941
           Computer       indoor      416.461538
                          outdoor     413.555556
           Heater         indoor     2143.277778
                          outdoor    2286.461538
           Lights         indoor     1447.950000
                          outdoor    3092.454545
           Microwave      indoor     1536.857143
                          outdoor    1429.294118
           Refridgerator  indoor      207.416667
                          outdoor     234.684211
           Television     indoor      251.000000
                          outdoor     249.904762

我确实在框架上尝试过{'00:00:00' : {'AC': {'indoor': 1362.2142857142858, 'outdoor': 3470.705882352941}, 'Computer': {'indoor': 399.0, 'outdoor': 412.4}, 'Heater': {'indoor': 2258.375, 'outdoor': 2274.6666666666665}, 'Lights': {'indoor': 1535.0, 'outdoor': 3475.4736842105262}, 'Microwave': {'indoor': 1420.0, 'outdoor': 1489.9333333333334}, 'Refridgerator': {'indoor': 192.38888888888889, 'outdoor': 195.07692307692307}, 'Television': {'indoor': 243.66666666666666, 'outdoor': 261.5}}, '00:00:01' : {'AC': {'indoor': 1493.0714285714287, 'outdoor': 3724.3529411764707}, 'Computer': {'indoor': 416.46153846153845, 'outdoor': 413.55555555555554}, 'Heater': {'indoor': 2143.277777777778, 'outdoor': 2286.4615384615386}, 'Lights': {'indoor': 1447.95, 'outdoor': 3092.4545454545455}, 'Microwave': {'indoor': 1536.857142857143, 'outdoor': 1429.2941176470588}, 'Refridgerator': {'indoor': 207.41666666666666, 'outdoor': 234.68421052631578}, 'Television': {'indoor': 251.0, 'outdoor': 249.9047619047619}}}和.agg()，但最终使用了不同的格式 .unstack()也没有给出令人满意的结果。它返回不同的格式

使用以下代码，我能做到的最好

.to_dict()

不给出预期的输出

df_devices.unstack(level=2).unstack().to_dict('index')

Answer 1

我假设数据帧是逗号分隔的数据帧，并以名称a.csv存储。以下是一种方法，您可以遍历每一行并从数据框中形成字典。

<div id="PRODUCT_DETAILS" class="modal fade"  tabindex="-1" role="dialog" aria-labelledby="myModalLabel">
        <div class="modal-dialog" role="document">                   
            <div class="modal-content">
                <div class="modal-header">
                    <button type="button" class="close" data-dismiss="modal" aria-label="Close"><span aria-hidden="true">&times;</span></button>
                    <h4 class="modal-title" id="myModalLabel"><?php echo $row['pro_name'];?></h4>
                </div>
                <div class="modal-body product_detail">
                    <div class="col-md-5 modal_body_left">
                        <img src="../products_images/<?php echo $row['pro_img']; ?>" alt=" " class="width-azset img-responsive">
                    </div>
                    <div class="col-md-7 modal_body_right">
                        <h4><?php echo $row['pro_name'];?></h4>
                        <p><?php echo $row['pro_dis'];?></p>

                        <div class="modal_body_right_cart simpleCart_shelfItem">
                            <p><i class="item_price"><?php echo $row['pro_price'];?></i></p>                            
                        </div>                  
                    </div>                  
                    <div class="clearfix"> </div>                   
                </div>
                <div class="modal-footer">
                    <button type="submit" name="Add_Cart" class="btn btn-success">Add to Cart</button>
                    <button type="button" class="btn btn-danger" data-dismiss="modal">Cancel</button>
                </div>
            </div>
        </div>
</div>

如果您找到比这更好的东西，请告诉我。谢谢。希望对您有所帮助。

Answer 2

我能够使用与我创建的相同的dict来解决

dicto = df_devices.unstack(level=2).unstack().to_dict('index')

>>> dicto

{'00:00:00': {('indoor', 'AC'): 1362.2142857142858,
('indoor', 'Computer'): 399.0,
('indoor', 'Heater'): 2258.375,
('indoor', 'Lights'): 1535.0,
('indoor', 'Microwave'): 1420.0,
('indoor', 'Refridgerator'): 192.38888888888889,
('indoor', 'Television'): 243.66666666666666,
('outdoor', 'AC'): 3470.705882352941,
('outdoor', 'Computer'): 412.4,
('outdoor', 'Heater'): 2274.6666666666665,
('outdoor', 'Lights'): 3475.4736842105262,
('outdoor', 'Microwave'): 1489.9333333333334,
('outdoor', 'Refridgerator'): 195.07692307692307,
('outdoor', 'Television'): 261.5}

浏览创建的字典，

df_dict = {}
df_type = {}

for i, j in dicto.items():
    for key, value in j.items():
        df_type[key[1]] = value
        df_dict[key[0]] = df_type.copy()
    dicto[i] = df_dict.copy()

.copy()用于创建副本而不是引用

>>> dicto
{'00:00:00': {'AC': {'indoor': 1362.2142857142858,
 'outdoor': 3470.705882352941},
 'Computer': {'indoor': 399.0, 'outdoor': 412.4},
 'Heater': {'indoor': 2258.375, 'outdoor': 2274.6666666666665},
 'Lights': {'indoor': 1535.0, 'outdoor': 3475.4736842105262},
 'Microwave': {'indoor': 1420.0, 'outdoor': 1489.9333333333334},
 'Refridgerator': {'indoor': 192.38888888888889,
 'outdoor': 195.07692307692307},
 'Television': {'indoor': 243.66666666666666, 'outdoor': 261.5}}.........

Python：pandas groupby到基于索引的字典

2 个答案: