Question

我正在使用python编写Discord机器人，但遇到了问题。我希望机器人打印接收到的消息，但是它执行了两次。而且我不知道为什么要打印两次。

https://github.com/PGillner/Discord-IPL-Bot/tree/master

上面是导致问题的3个“模块”的链接，它尚在开发中，没有太多的代码，应该相当容易浏览。感谢您对其为何两次打印的任何帮助！

Main.py

import discord
import asyncio
from discord import Status

from Status import Member_Status
from User import User_Who
from Matchmaking import MM

runtime = 0

client = discord.Client()

@client.event
async def on_member_update(before, after):
    await Member_Status(before, after) ## Complete

@client.event
async def on_message(message):
    await User_Who(message) ##Incomplete
    if await User_Who(message):
        await client.delete_message(message)

async def my_background_task():
    await client.wait_until_ready()
    while not client.is_closed:
        global run_time
        await MM() ##Incomplete
        print("Runtime: {}s".format(runtime))
        runtime += 10
        await asyncio.sleep(10)

@client.event
async def on_ready():
    print("------Logged in as------")
    print("        {}".format(client.user.name))
    print("   {}".format(client.user.id))
    print("------------------------")

client.loop.create_task(my_background_task())
client.run("NDU0OTQ1NTcyNzI2NzY3NjI3.Df04DA.paEHHr5h1frdHFLsth2THp7FFBs")

User.py

import discord
import asyncio

from Print import Print_MSG
from Queue_join import Queue_Join
from Queue_leave import Queue_Leave
from match_room_1 import M_R_1
from match_room_2 import M_R_2
from match_room_3 import M_R_3
from match_room_4 import M_R_4
from match_room_5 import M_R_5

client = discord.Client()

async def User_Who(message):
    if message.author != client.user:
        await Print_MSG(message) ## Complete
        if str(message.channel) == "queue":
            if message.content.startswith("!join"):
                await Queue_Join() ##Incomplete
            elif message.content.startswith("!leave"):
                await Queue_Leave() ##Incomplete
            else:
                return True
        elif str(message.channel) == "match_room_1":
            await M_R_1() ##Incomplete
        elif str(message.channel) == "match_room_1":
            await M_R_2() ##Incomplete
        elif str(message.channel) == "match_room_1":
            await M_R_3() ##Incomplete
        elif str(message.channel) == "match_room_1":
            await M_R_4() ##Incomplete
        elif str(message.channel) == "match_room_1":
            await M_R_5() ##Incomplete

Print.py

import discord
import asyncio

async def Print_MSG(message):
    timestamp = str(message.timestamp)
    timestamp = timestamp[:-7]
    timestamp = timestamp[11:]
    print("Channel: {} | {} [{}]: {}".format(message.channel, timestamp, message.author, message.content))

Answer 1

await User_Who(message) ##Incomplete
if await User_Who(message):

您的User_Who协程运行两次，每个协程包含Print_MSG。

is_complete = await User_Who(message) ##Incomplete
if is_complete:

此外，您正在过度使用async / await。我可以知道您为什么也为Print_MSG这么做的原因吗？它只是打印消息。

Python打印两次

1 个答案: