Question

fqas = None
while fqas not in ("yes", "no", "Yes", "No"):
    fqas = input(">>> [yes/no]: ")
    if fqas.lower() == "yes":
         print("\nAwesome! Current pay: $", base_pay + 50)
    elif fqas.lower() == "no":
        fqas_no = int(input("if not, how much do you think she deserve? \n>>> "))
        if 50 <= fqas_no :
            print("AMAZINGGGG! current pay: $", base_pay + fqas_no)
            continue
        elif fqas_no <= 50 :
            print("That's cool, current pay: $", base_pay + fqas_no)
            continue
        except ValueError:
            print("Numbers only please")

如何添加最后一个循环来检查fqas_no下的整数？我已检查范围，但无法获取整数。尝试使用SyntaxError时收到无效的ValueError。

除了：

之外，该代码均正常运行

        except ValueError:
             print("Numbers only please")

Answer 1

看看documentation有关异常处理的信息。您需要包含一个try语句：

try:
    if 50 <= fqas_no :
        #etc
except ValueError:
    print("Numbers only please")

这两个在一起。仅使用except是错误的语法。

旁注，您应该在输入本身上调用lower()。这样，您的代码就会更干净：

while fqas not in ["yes", "no"]:
    fqas = input(">>> (yes/no): ").lower()
    if fqas == "yes":
        #etc

Answer 2

您已经知道如何循环直到获得有效（或无效）输入。要检测整数，您可以尝试将输入转换为int

try:
    value = int(fqas_no)
except:
    # loop around to try again

更好，请使用内置方法

if fqas_no.isdigit():

Answer 3

您可能会遇到问题，这是您的问题。

base_pay = 1000
fqas = None
while fqas not in ("yes", "no", "Yes", "No"):
    fqas = input(">>> [yes/no]: ")

    if fqas.lower() == "yes":
        print("\nAwesome! Current pay: $", base_pay + 50)
    elif fqas.lower() == "no":
    try:
        fqas_no = int(input("if not, how much do you think she deserve? \n>>>"))
    except ValueError:
        print('Numbers only please')
        break

    if 50 <= fqas_no:
        print("AMAZINGGGG! current pay: $", base_pay + fqas_no)
        continue

    elif fqas_no <= 50:
        print("That's cool, current pay: $", base_pay + fqas_no)
        continue

这应该可以解决您的问题。

如何在循环下检查整数？

3 个答案: