Question

我正在尝试将RealmList的RealmList从服务器（JSON）获取到realm对象。我正在

错误：RealmList的元素类型必须是实现“ RealmModel”的类，或者是“ java.lang.String”，“ byte []”，“ java.lang.Boolean”，“ java.lang.Long”之一，'java.lang.Integer'，'java.lang.Short'，'java.lang.Byte'，'java.lang.Double'，'java.lang.Float'，'java.util.Date'。< / p>

{
 "facilities": [
{
  "facility_id": "1",
  "name": "Property Type",
  "options": [
    {
      "name": "Apartment",
      "icon": "apartment",
      "id": "1"
    },
    {
      "name": "Condo",
      "icon": "condo",
      "id": "2"
    },
    {
      "name": "Boat House",
      "icon": "boat",
      "id": "3"
    },
    {
      "name": "Land",
      "icon": "land",
      "id": "4"
    }
  ]
},
{
  "facility_id": "2",
  "name": "Number of Rooms",
  "options": [
    {
      "name": "1 to 3 Rooms",
      "icon": "rooms",
      "id": "6"
    },
    {
      "name": "No Rooms",
      "icon": "no-room",
      "id": "7"
    }
  ]
},
{
  "facility_id": "3",
  "name": "Other facilities",
  "options": [
    {
      "name": "Swimming Pool",
      "icon": "swimming",
      "id": "10"
    },
    {
      "name": "Garden Area",
      "icon": "garden",
      "id": "11"
    },
    {
      "name": "Garage",
      "icon": "garage",
      "id": "12"
    }
  ]
}
],
 "exclusions": [
[
  {
    "facility_id": "1",
    "options_id": "4"
  },
  {
    "facility_id": "2",
    "options_id": "6"
  }
],
[
  {
    "facility_id": "1",
    "options_id": "3"
  },
  {
    "facility_id": "3",
    "options_id": "12"
  }
],
[
  {
    "facility_id": "2",
    "options_id": "7"
  },
  {
    "facility_id": "3",
    "options_id": "12"
  }
]
]
}

Answer 1

尝试此解决方案

public class Exclusion extends RealmObject {
    private int facilityId;
    private int optionsId;
}

public class Exclusions extends RealmObject {
private RealmList<Exclusion> exclusions;
}

所以现在您可以使用RealmList<Exclusions> exclusionsRealmList作为合法的领域列表

希望这会有所帮助

Answer 2

Gianthran的答案很接近，但您也应该建立关系。

 public class Exclusion extends RealmObject {
     @Index
     private int facilityId;
     @Index
     private int optionsId;

     private Facility facility;

     private Option option;
 }

和

 public class Facility extends RealmObject {
      @LinkingObjects("facility")
      private final RealmResults<Exclusion> exclusions = null;
 }

 public class Option extends RealmObject {
      @LinkingObjects("option")
      private final RealmResults<Exclusion> exclusions = null;
 }

我认为Exclusions对象不是必需的，我希望该表在某种程度上已经是一个集合。

Answer 3

在使用retorfit 2时如何使用嵌套的RealmList？并摆脱错误：RealmList的元素类型必须是实现“ RealmModel”的类

假设我的Json是这样的：

{
  "data": {
    "options": [
      [
        {
          "name": "abc",
          "id": 1,
          "type": "profile"
        },
        {
          "name": "def",
          "id": 2,
          "type": "profile"
        }
      ],
      [
        {
          "name": "abc",
          "id": 1,
          "type": "business_profile"
        },
        {
          "name": "def",
          "id": 2,
          "type": "business_profile"
        }
      ]
    ]
  }
}

我的POJO类似于

-----------------------------------com.example.Data.java-----------------------------------

package com.example;

import java.util.List;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Data {

@SerializedName("options")
@Expose
private List<List<Option>> options = null;

public List<List<Option>> getOptions() {
return options;
}

public void setOptions(List<List<Option>> options) {
this.options = options;
}

}
-----------------------------------com.example.Example.java-----------------------------------

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Example {

@SerializedName("data")
@Expose
private Data data;

public Data getData() {
return data;
}

public void setData(Data data) {
this.data = data;
}

}
-----------------------------------com.example.Option.java-----------------------------------

package com.example;

import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;

public class Option {

@SerializedName("name")
@Expose
private String name;
@SerializedName("id")
@Expose
private Integer id;
@SerializedName("type")
@Expose
private String type;

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public Integer getId() {
return id;
}

public void setId(Integer id) {
this.id = id;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

}

将对象转换为RealmObject时，我需要将RealmObject扩展到我的对象类，但是我需要将List替换为RealList，这在一个级别上是可能的，但是在编写RealmList>时，会给我错误。

我试图通过创建GenericList来解决。

public class GenericList<T extends RealmObject> extends RealmObject {
    private RealmList<T> fieldList = new RealmList<>();

    public RealmList<T> getFieldList() {
        return fieldList;
    }

    public void setFieldList(RealmList<T> fieldList) {
        this.fieldList = fieldList;
    }
}

在Pojo中进行了更改，例如

public class Data {

    @SerializedName("options")
    @Expose
    private RealmList<GenericList<Option>> options = null;

    public RealmList<GenericList<Option>> getOptions() {
    return options;
    }

    public void setOptions(RealmList<GenericList<Option>> options) {
    this.options = options;
    }

    }

但这会产生错误：预期

如何在Android中创建RealmList <realmlist <object >>

3 个答案: