使用枢轴功能，我设法获得了扁平数据框：
q_id 1 2
a_id 1 2 3 4 5 6 7 8
movie_id user_id start_rating
931 284 2.0 0 0 0 1 0 0 0 0
804 648 4.5 0 0 0 0 1 0 0 0
840 414 4.5 0 1 0 0 0 0 0 0
843 419 3.5 1 0 0 0 0 1 0 0
848 132 3.5 1 0 0 1 0 0 0 0
我的目标是删除索引和列名的附加级别。
movie_id user_id start_rating 1_1 1_2 1_3 1_4 2_5 2_6 2_7 2_8
931 284 2.0 0 0 0 1 0 0 0 0
804 648 4.5 0 0 0 0 1 0 0 0
840 414 4.5 0 1 0 0 0 0 0 0
843 419 3.5 1 0 0 0 0 1 0 0
848 132 3.5 1 0 0 1 0 0 0 0
我尝试了以下步骤：
df.columns = ['_'.join(col).strip() for col in df.columns.values]
但得到：
df.columns = ['_'.join(col).strip() for col in df.columns.values]
TypeError: sequence item 0: expected string, int found
答案 0 :(得分：1)
函数join适用于字符串，错误显示col的元素为 SpeechToText speechToText = new SpeechToText();
speechToText.setEndPoint("https://stream.watsonplatform.net/speech-to-text/api/v1/recognize");
speechToText.setUsernameAndPassword("{myUsername}", "{myPassword}");
try {
RecognizeOptions recognizeOptions = new RecognizeOptions.Builder()
.audio(new FileInputStream("KATL-App-Final-All-Aug-01-2017-1630.mp3-edited.mp3"))
.contentType("audio/mp3")
.model("en-US_NarrowbandModel")
.interimResults(true)
.build();
BaseRecognizeCallback baseRecognizeCallback
= new BaseRecognizeCallback() {
@Override
public void onListening() {
System.out.println("Listening");
}
@Override
public void onConnected() {
System.out.println("Connected");
}
@Override
public void onTranscription(SpeechRecognitionResults speechRecognitionResults) {
System.out.println(speechRecognitionResults);
}
@Override
public void onDisconnected() {
System.exit(0);
}
};
speechToText.recognizeUsingWebSocket(recognizeOptions,
baseRecognizeCallback);
} catch (FileNotFoundException e) {
e.printStackTrace();
}
for (;;) {
Thread.sleep(1000);
}
。您需要将int的元素转换为col。
str或者因为这里有两个级别，请执行以下操作：
df.columns = ['_'.join([str(lev) for lev in col]).strip() for col in df.columns.values]