在数组python中查找包含关键字的值的索引

时间:2018-06-21 16:15:09

标签: python list

我想找到数组中包含关键字的值的索引。

例如:

.btn-primary {
    color: #212529;
    background-color: #7cc;
    border-color: #5bc2c2
}

.btn-primary:hover {
    color: #212529;
    background-color: #52bebe;
    border-color: #8ad3d3
}

.btn-primary:focus,
.btn-primary.focus {
    box-shadow: 0 0 0 .2rem rgba(91, 194, 194, 0.5)
}

.btn-primary.disabled,
.btn-primary:disabled {
    color: #212529;
    background-color: #7cc;
    border-color: #5bc2c2
}

.btn-primary:not(:disabled):not(.disabled):active,
.btn-primary:not(:disabled):not(.disabled).active,
.show>.btn-primary.dropdown-toggle {
    color: #212529;
    background-color: #9cdada;
    border-color: #2e7c7c
}

.btn-primary:not(:disabled):not(.disabled):active:focus,
.btn-primary:not(:disabled):not(.disabled).active:focus,
.show>.btn-primary.dropdown-toggle:focus {
    box-shadow: 0 0 0 .2rem rgba(91, 194, 194, 0.5)
}

.btn-outline-primary {
    color: #7cc;
    background-color: transparent;
    background-image: none;
    border-color: #7cc
}

.btn-outline-primary:hover {
    color: #222;
    background-color: #8ad3d3;
    border-color: #7cc
}

.btn-outline-primary:focus,
.btn-outline-primary.focus {
    box-shadow: 0 0 0 .2rem rgba(119, 204, 204, 0.5)
}

.btn-outline-primary.disabled,
.btn-outline-primary:disabled {
    color: #7cc;
    background-color: transparent
}

.btn-outline-primary:not(:disabled):not(.disabled):active,
.btn-outline-primary:not(:disabled):not(.disabled).active,
.show>.btn-outline-primary.dropdown-toggle {
    color: #212529;
    background-color: #8ad3d3;
    border-color: #7cc
}

.btn-outline-primary:not(:disabled):not(.disabled):active:focus,
.btn-outline-primary:not(:disabled):not(.disabled).active:focus,
.show>.btn-outline-primary.dropdown-toggle:focus {
    box-shadow: 0 0 0 .2rem rgba(119, 204, 204, 0.5)
}

我想获取A = ['a1','b1','a324'] keyword = 'a' 的索引[0,2]

我尝试了这个a1, a324 但是获取list(filter(lambda x:'a' in x, A))而不是索引。

2 个答案:

答案 0 :(得分:2)

enumerate用于列表理解:

A = ['a1','b1','a324']
keyword = 'a'

print([i for i, x in enumerate(A) if keyword in x])
# [0, 2]

答案 1 :(得分:2)

简单地写:

A = ['a1','b1','a324']
keyword = 'a'
indices = [i for i in range(len(A)) if keyword in A[i]]
print(indices)