Question

am尝试使用多个关联行的数据库中的数据将它们提取到ROW1，ROW2和ROW3中，但使用

<?php echo $row['']; ?>

但是它不起作用，请提出任何想法

这是我的代码

<?php
$sql = "SELECT * FROM songs ORDER BY id DESC LIMIT 2,1;";
$result = mysqli_query($con, $sql);
$resultCheck = mysqli_num_rows($result);

if (mysqli_num_rows($result) > 0) {
    while ($row = mysqli_fetch_assoc($result)) {

}
?>

<li>
<a href="single.html"><img src="images/<?php echo $row['photo']; ?>" alt=""/> 
</a>
<div class="slide-title"><h4><?php echo $row['song_name']; ?></div>
<div class="slide-title"><h4><?php echo $row['artist']; ?></div>
<div button class="btn btn-large btn-primary" type="button">BUY</div>
</li>

Answer 1

在回显结果之前，您似乎正在关闭while循环。只需在结束}之后移动结束括号</li>

您的代码应如下所示：

<?php
$sql = "SELECT * FROM songs ORDER BY id DESC LIMIT 2,1;";
$result = mysqli_query($con, $sql);
$resultCheck = mysqli_num_rows($result);

if ($resultCheck > 0) {
    while ($row = mysqli_fetch_assoc($result)) {
?>
<li>
<a href="single.html"><img src="images/<?php echo $row['photo']; ?>" alt=""/> 
</a>
<div class="slide-title"><h4><?php echo $row['song_name']; ?></div>
<div class="slide-title"><h4><?php echo $row['artist']; ?></div>
<div button class="btn btn-large btn-primary" type="button">BUY</div>
</li>
<?php
    }
}
?>

Answer 2

尝试此代码

<?php
$sql = "SELECT * FROM songs ORDER BY id DESC LIMIT 2,1;";
$result = mysqli_query($con, $sql);
$resultCheck = mysqli_num_rows($result);

if ($resultCheck > 0) {
    while ($row = mysqli_fetch_assoc($result)) {
        foreach ($row as $data) {
?>
<li>
<a href="single.html"><img src="images/<?php echo $row['photo']; ?>" alt=""/> 
</a>
<div class="slide-title"><h4><?php echo $data['song_name']; ?></div>
<div class="slide-title"><h4><?php echo $data['artist']; ?></div>
<div button class="btn btn-large btn-primary" type="button">BUY</div>
</li>
<?php
        }
    }
}
?>

如何通过php将mysql中的这些数据插入到我的网页中？

2 个答案: